In: Operations Management
activity | follows | optimistic duration | most likely direction | pessimistic duration |
A | - | 4 | 6 | 14 |
B | A,C | 3 | 4 | 5 |
C | - | 3 | 5 | 13 |
D | A,E | 12 | 18 | 24 |
E | - | 8 | 10 | 18 |
F | A,E | 4 | 6 | 8 |
G | B,F | 7 | 8 | 9 |
H | G | 10 | 12 | 14 |
I | G | 5 | 6 | 7 |
J | D,I | 5 | 7 | 9 |
a) Calculate mean duration and standard deviation for all the
activities using the beta distribution. [4pts]
b) Construct a network diagram for this problem using the mean
durations calculated in part (a), calculate the LS(Foll.),
ES(Prec.) and total float for all the activities, and hence
identify the critical path . What is the mean completion time for
the project? What is the standard deviation of the critical path?
[30 pts ]
c) What is the 92% confidence interval for the length of the
critical path? [4 pts]
d) Assuming the probability distribution of the length of the
critical path can be approximated by a normal distribution with the
mean and standard deviation calculated in part (b), calculate the
probability of completing the project within 42 weeks. [4
pts]
e) Calculate the probability of completing the project between 35
and 40 weeks? [4 pts]
f) Answer the project manager’s question: “I want to tell the
client that there is a 10.03% chance the project will take longer
than X weeks - what figure should I give them (i.e. find X)?”
[4]
(please show work step by step and excel file)
Activity | To | Tm | Tp | Te | (Var)^0.5 | Var |
A | 4 | 6 | 14 | 7 | 1.666667 | 2.777778 |
B | 3 | 4 | 5 | 4 | 0.333333 | 0.111111 |
C | 3 | 5 | 13 | 6 | 1.666667 | 2.777778 |
D | 12 | 18 | 24 | 18 | 2 | 4 |
E | 8 | 10 | 18 | 11 | 1.666667 | 2.777778 |
F | 4 | 6 | 8 | 6 | 0.666667 | 0.444444 |
G | 7 | 8 | 9 | 8 | 0.333333 | 0.111111 |
H | 10 | 12 | 14 | 12 | 0.666667 | 0.444444 |
I | 5 | 6 | 7 | 6 | 0.333333 | 0.111111 |
J | 5 | 7 | 9 | 7 | 0.666667 | 0.444444 |
Activity | ES | EF | LS | LF | Slack |
A | 0 | 7 | 6 | 13 | 6 |
B | 7 | 11 | 13 | 17 | 6 |
C | 0 | 6 | 7 | 13 | 7 |
D | 11 | 29 | 13 | 31 | 2 |
E | 0 | 11 | 0 | 11 | 0 |
F | 11 | 17 | 11 | 17 | 0 |
G | 17 | 25 | 17 | 25 | 0 |
H | 25 | 37 | 26 | 38 | 1 |
I | 25 | 31 | 25 | 31 | 0 |
J | 31 | 38 | 31 | 38 | 0 |
Critical path is EFGIJ with duration 38.
Variance of the CP=3.8887
SD of critical path = (3.8887)^0.5 =1.9719
Time for 92% probability is given by
z = T-38/1.9719
z =1.41
1.41 = T-38/1.9719
T =40.78
(d) Prob. that the project will be completed within 42 weeks
z = 42-38/1.9719 =2.02
which gives a probability of 0.9783
Note : As per policies, I can answer first 4 parts of a problem. Inconvenience is regretted