Question

In: Operations Management

activity follows optimistic duration most likely direction pessimistic duration A - 4 6 14 B A,C...

activity follows optimistic duration most likely direction pessimistic duration
A - 4 6 14
B A,C 3 4 5
C - 3 5 13
D A,E 12 18 24
E - 8 10 18
F A,E 4 6 8
G B,F 7 8 9
H G 10 12 14
I G 5 6 7
J D,I 5 7 9

a) Calculate mean duration and standard deviation for all the activities using the beta distribution. [4pts]
  
b) Construct a network diagram for this problem using the mean durations calculated in part (a), calculate the LS(Foll.), ES(Prec.) and total float for all the activities, and hence identify the critical path . What is the mean completion time for the project? What is the standard deviation of the critical path? [30 pts ]
  
c) What is the 92% confidence interval for the length of the critical path? [4 pts]
  
d) Assuming the probability distribution of the length of the critical path can be approximated by a normal distribution with the mean and standard deviation calculated in part (b), calculate the probability of completing the project within 42 weeks. [4 pts]

e) Calculate the probability of completing the project between 35 and 40 weeks? [4 pts]
  
f) Answer the project manager’s question: “I want to tell the client that there is a 10.03% chance the project will take longer than X weeks - what figure should I give them (i.e. find X)?” [4]

(please show work step by step and excel file)

Solutions

Expert Solution

Activity To Tm Tp Te (Var)^0.5 Var
A 4 6 14 7 1.666667 2.777778
B 3 4 5 4 0.333333 0.111111
C 3 5 13 6 1.666667 2.777778
D 12 18 24 18 2 4
E 8 10 18 11 1.666667 2.777778
F 4 6 8 6 0.666667 0.444444
G 7 8 9 8 0.333333 0.111111
H 10 12 14 12 0.666667 0.444444
I 5 6 7 6 0.333333 0.111111
J 5 7 9 7 0.666667 0.444444
Activity ES EF LS LF Slack
A 0 7 6 13 6
B 7 11 13 17 6
C 0 6 7 13 7
D 11 29 13 31 2
E 0 11 0 11 0
F 11 17 11 17 0
G 17 25 17 25 0
H 25 37 26 38 1
I 25 31 25 31 0
J 31 38 31 38 0

Critical path is EFGIJ with duration 38.

Variance of the CP=3.8887

SD of critical path = (3.8887)^0.5 =1.9719

Time for 92% probability is given by

z = T-38/1.9719

z =1.41

1.41 = T-38/1.9719

T =40.78

(d) Prob. that the project will be completed within 42 weeks

z = 42-38/1.9719 =2.02

which gives a probability of 0.9783

Note : As per policies, I can answer first 4 parts of a problem. Inconvenience is regretted


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