In: Operations Management
activity | follows | optimistic duration | most likely direction | pessimistic duration |
A | - | 4 | 6 | 14 |
B | A,C | 3 | 4 | 5 |
C | - | 3 | 5 | 13 |
D | A,E | 12 | 18 | 24 |
E | - | 8 | 10 | 18 |
F | A,E | 4 | 6 | 8 |
G | B,F | 7 | 8 | 9 |
H | G | 10 | 12 | 14 |
I | G | 5 | 6 | 7 |
J | D,I | 5 | 7 | 9 |
Calculate the probability of completing the project between 35
and 40 weeks? [4 pts]
f Answer the project manager’s question: “I want to tell the client
that there is a 10.03% chance the project will take longer than X
weeks - what figure should I give them (i.e. find X)?”
[4]
We need to calcuate the project duration using the critical path method / PERT. The expected duration is
E = (optimistic + 4*most likely + pessimistic) / 6
Variance = ((pessimistic - optimistic)/6)^2
The calculated values are shown below
The exxpected duration is 38 weeks and the variance for this duration is 3.88 weeks.
The z value for less 35 weeks = (35-38)/sqrt(3.88) = -1.52
The corresponding probability = 0.063
The z value for less than 40 weeks = (40-38)/sqrt(3.88) = 1.01
The corresponding probability = 0.845
The range between 35 to 40 weeks = 0.845-0.063 = 0.782
The probability of finishing between 35 and 40 weeks is 0.782
A 10.03% probability means that the z value is -1.27
This means -1.27 = (X-38)/sqrt(3.88) or X = 35.47 weeks