Question

In: Operations Management

activity follows optimistic duration most likely direction pessimistic duration A - 4 6 14 B A,C...

activity follows optimistic duration most likely direction pessimistic duration
A - 4 6 14
B A,C 3 4 5
C - 3 5 13
D A,E 12 18 24
E - 8 10 18
F A,E 4 6 8
G B,F 7 8 9
H G 10 12 14
I G 5 6 7
J D,I 5 7 9

Calculate the probability of completing the project between 35 and 40 weeks? [4 pts]
  
f Answer the project manager’s question: “I want to tell the client that there is a 10.03% chance the project will take longer than X weeks - what figure should I give them (i.e. find X)?” [4]

Solutions

Expert Solution

We need to calcuate the project duration using the critical path method / PERT. The expected duration is

E = (optimistic + 4*most likely + pessimistic) / 6

Variance = ((pessimistic - optimistic)/6)^2

The calculated values are shown below

The exxpected duration is 38 weeks and the variance for this duration is 3.88 weeks.

The z value for less 35 weeks = (35-38)/sqrt(3.88) = -1.52

The corresponding probability = 0.063

The z value for less than 40 weeks = (40-38)/sqrt(3.88) = 1.01

The corresponding probability = 0.845

The range between 35 to 40 weeks = 0.845-0.063 = 0.782

The probability of finishing between 35 and 40 weeks is 0.782

A 10.03% probability means that the z value is -1.27

This means -1.27 = (X-38)/sqrt(3.88) or X = 35.47 weeks


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