Question

In: Math

Assume that x is a binomial random variable with n = 100 and p = 0.40....

Assume that x is a binomial random variable with n = 100 and p = 0.40. Use a normal
approximation (BINOMIAL APPROACH) to find the following: **please show all work**
c. P(x ≥ 38) d. P(x = 45) e. P(x > 45) f. P(x < 45)

Solutions

Expert Solution

Solution :

Given that,

p = 0.40

q = 1 - p =1-0.40=0.60

n = 100

Using binomial distribution,

= n * p = 100*0.40=40

= n * p * q = 100*0.40*0.60=4.8990

Using continuity correction ,

(C)P(x ≥ 38 ) = 1 - P(x <37.5)

= 1 - P((x - ) / < (37.5 - 40) /4.8990 )

= 1 - P(z <-0.51 )

= 1 - 0.3050

=0.6950

(d)Using continuity correction ,

P(x = 45)= P[(44.5 - 40)/4.8990 ) < (x - ) / < (45.5 - 40) /4.8990 ]

= P( 0.92< z < 1.12)

= P(z <1.12 ) - P(z <0.92 )

=0.8686 - 0.8212

=0.0474

(E)P(x >45 ) = 1 - P(x <45)

= 1 - P((x - ) / < (45.5 - 40) /4.8990 )

= 1 - P(z <1.12 )

= 1 - 0.8686

=0.1314

(F)P(x <45 )= P((x - ) / < (44.5 - 40) /4.8990 )

= P(z <0.92 )   

=0.8212


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