In: Chemistry
5.00 moles of N2 and 8.00 moles of H2 are placed in an empty container, the container is heated to 887 degrees Celsius, and a catalyst is added that catalyzes the rxn. of these gases to form NH3 as the only product. At equilibrium 1.00 mole of NH3 is found to be present. Find number of moles N2 and moles H2 present at equilibrium.
* I think that the concentrations of the reactants changes by 1 mole but I'm not enitrely sure if that is correct.
N2 + 3 H2 <-----------------------> 2 NH3
5 8 0 ----------------------> initial
-x -3x +2x ---------------------> decomposition
5-x 8-3x 2x ---------------------------> equilibrium
equilibrium NH3 moles = 1.0
2x = 1.0
x = 0.5
equilibrium moles of N2 : 5 -x = 5 -0.5 = 4.5 mol
equilibrium moles of H2 : 8 -3x = 8 - 3 x 0.5 = 6.5 mol