Question

In: Chemistry

One mole of N2 and 3 moles of H2 are placed in a flask at 397°C....

One mole of N2 and 3 moles of H2 are placed in a flask at 397°C. Calculate the total pressure of the system at equilibrium if the mole fraction of NH3 is found to be 0.258. The KP for the reaction is 4.31 × 10^-4

Expert Solution

N2 (g) + 3 H2 (g) <----------> 2 NH3 (g)

1 mol 3 mol 0 mol

1 - x 3 -3x 2x

mole fraction of NH3 = 0.258

mole fraction of N2 = (1-0.258) x 1 / 1 + 3 = 0.1855

mole fraction of H2 = (1-0.258) x 3 / 1 + 3 = 0.5565

ratio : N2 : H2 : NH3

0.1855 0.5565 : 0.21

1 3 1.13

PH2 = 3x

PN2 = x

PNH3 = 1.13 x

Kp = (1.13x)^2 / x (3x)^3

4.31 × 10^-4 = 1.282x^2 / 27 x^4

x = 10.5

total pressure = 53.8 bar

queen_honey_blossom answered 2 years ago

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