How many moles of H2 and N2 can be formed by the decomposition of 2.56 mol...

How many moles of H₂ and N₂ can be formed by the decomposition of 2.56 mol of ammonia, NH₃?

Expert Solution

2 NH3 --------------------> N2 + 3 H2

2 1 3

2.56 ? ?

for 2 moles of NH3 ------------------ 1 mol of N2

for 2.56 mol of NH3 ------------------- ??

moles of N2 = 2.56 x 1 / 2 = 1.28 moles

for 2 moles of NH3 ------------------ 3 mol of H2

for 2.56 mol of NH3 ------------------- ??

moles of H2 = 2.56 x 3 / 2 = 3.84 moles

queen_honey_blossom answered 2 years ago

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