At a certain temperature, 0.4011 mol of N2 and 1.581 mol of H2 are placed in...

At a certain temperature, 0.4011 mol of N2 and 1.581 mol of H2 are placed in a 1.50L container. N2(g) + 3H2(g) −⇀↽− 2NH3(g) At equilibrium, 0.1401 mol of N2 is present. Calculate the equilibrium constant, Kc.

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queen_honey_blossom answered 1 year ago

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At a certain temperature, 0.4011 mol of N2 and 1.581 mol of H2 are placed in...

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