In: Chemistry
2.00 moles of CO2 and 1.50 moles of H2 are placed into a rigid 5.00-L container and they react according to the equation ? ? CO2(g) + H2(g) ? CO(g) + H2O(g) ? ? K = 2.50 What will be the concentration of carbon monoxide when equilibrium is reached?
2.00 moles of CO2 and 1.50 moles of H2 are placed into a rigid 5.00-L container and they react according to the equation ? ? CO2(g) + H2(g) ? CO(g) + H2O(g) ? ? K = 2.50 What will be the concentration of carbon monoxide when equilibrium is reached?
Initial concentration of CO2 = moles / volume = 2 / 5 = 0.4 M
Initial concentraiton of H2 = moles / volume = 1.5 /5 = 0.3 M
The equation is
CO2(g) + H2(g) ===> CO(g) + H2O(g)
Initial 0.4 0.3 0 0
Change -x -x +x +x
Equilibrium 0.4-x 0.3-x x x
Kc = 2.50 = [CO] [ H2O] / [CO2][H2] = x2 / (0.4-x)(0.3-x) = 2.50
x2 = 2.50 [(0.4-x)(0.3-x)]
x2 = 2.50x2 + 0.3 - 0.6x
1.50 x2 + 0.3 - 1.75x = 0
On solving
x = 0.209
[CO] = x = 0.209