How many moles of NH3 can be produced when 11.00 mol H2 react with 5.00 mol...

How many moles of NH3 can be produced when 11.00 mol H2 react with 5.00 mol N2?

_________mol NH3

How many moles of each reactant are left over? Note that at least one must disappear.

______mol H2 remain

_______mol N2 remain

Expert Solution

N2 + 3 H2 -------------------> 2 NH3

1mol 3 mol 2 mol

5 mol 11 mol ?

here limiting reagent is H2. so NH3 formed based on that.

3 mol H2 -------------- 2 mol NH3

11 mol H2 -------------- ?? NH3

moles of NH3 produced = 11 x 2 / 3

= 7.33 mol NH3

we need only 3.67 mol of N2. here we have 5 mol of N2 . so N2 is left over

moles of N2 remain = 5 - 3.67 = 1.33 mol N2

moles of H2 = 0 . it all consumed

queen_honey_blossom answered 2 years ago

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