a 46 lb. postoperative patient needs fluids at 75 ml/kg/day with lidocaine (2%) at 30ug/kg/min, ketamine (100 mg/ml) at 5 ug/kg/min, and morpine (10 mg/ml) at 2.5 (ug/kg/min).

a: what is the rate of fluids per hour

b: how many militers of medication to add to 1 L bag:

of lidocaine ? of Ketamine? of morphine??

PLEASE ANSWER ALL PARTS AND SHOW WORK

Describe or draw the endocrine control in the ovary beginning with the primary oocyte and ending with the degeneration of the corpus luteum. Be sure to include the hormones involved.

o carry out 'blue-white screening', the E.coli plasmid pUC18 carries:

** Prior, which I forgot to include:

All Vulcans have pointed ears (P) and a right-sided heart (R) which are dominant over Earthling alleles of rounded ears (p) and a left-sided heart (r). Both Vulcans and Earthlings are homozygous for each allele.

Mr. Spock has a Vulcan father and an Earthling mother.

Gametes produced by an individual that are the same as the gametes contributed by each parent to produce that individual are called parental types.

Gametes that have a combination of parental and maternal alleles are called recombinant types.

Recombinant gametes are the result of independent assortment during Metaphase I if genes are on different chromosomes or crossing over during prophase I if genes are on the same chromosome.

In which I got the following: PR, PP, pR,Pr

_______

In Vulcans, the absence of adrenal glands (A) is dominant over the Earthling allele for adrenal glands (a). All Earthlings have adrenal glands.

A gene map of Mr. Spock shows that the genes for ear shape (P/p) and heart sidedness (R/r) are 20 map units apart on chromosome 7 while the gene for adrenal glands (A/a) is on chromosome 3.

If Mr. Spock fathers a child with an Earthling female, what is the chance that the child will have pointed ears and adrenal glands?

Select one:

a. 10%

b. 20%

c. 25%

d. 50%

Can someone please show me how to get the proper answer? I keep getting myself confused on this self-check question, and I don't know where I keep messing up.

Thank you

Under anaerobic conditions, cells must sacrifice the pyruvate they made from glycolysis. Why?

You have three genes on the same chromosome - A, B and C. Each gene has two alleles in a dominant/recessive relationship. For these genes the homozygous recessive has the mutant phenotype for that trait, the dominant phenotype = wild type for that trait.

• allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A
• allele B is dominant to b; phenotype b = mutant for trait b; phenotype B = wild type for trait B
• allele C is dominant to c; phenotype c = mutant for trait c; phenotype C = wild type for trait C

Note: phenotypes can be represented by single letters. For example phenotype A = genotypes Aa or AA; phenotype a = genotype aa. Assume that phenotype ab = mutant phenotype for traits a and b, and wild type phenotype for trait C.

You cross an individual heterozygote for all three genes, with an individual who is homozygote recessive for all three. Out of 10,000 offspring you get the following phenotypes and amounts:

• phenotype a - 98
• phenotype b - 150
• phenotype c - 4751
• phenotype ab - 4749
• phenotype ac - 147
• phenotype bc - 99
• phenotype abc - 3
• wild type - 3

Use this information to answer the following questions.

Based on the information given and your answer to the previous questions, what was the genotype of the heterozygous parent, in the correct order?

Select one:

a. BAc/baC

b. ABC/abc

c. AcB/aCb

d. ACB/acb

e. ABc/abC

Where do processed mRNA’s go after leaving the nucleus and how? Explain

You have three genes on the same chromosome - A, B and C. Each gene has two alleles in a dominant/recessive relationship. For these genes the homozygous recessive has the mutant phenotype for that trait, the dominant phenotype = wild type for that trait.

• allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A
• allele B is dominant to b; phenotype b = mutant for trait b; phenotype B = wild type for trait B
• allele C is dominant to c; phenotype c = mutant for trait c; phenotype C = wild type for trait C

Note: phenotypes can be represented by single letters. For example phenotype A = genotypes Aa or AA; phenotype a = genotype aa. Assume that phenotype ab = mutant phenotype for traits a and b, and wild type phenotype for trait C.

You cross an individual heterozygote for all three genes, with an individual who is homozygote recessive for all three. Out of 10,000 offspring you get the following phenotypes and amounts:

• phenotype a - 98
• phenotype b - 150
• phenotype c - 4751
• phenotype ab - 4749
• phenotype ac - 147
• phenotype bc - 99
• phenotype abc - 3
• wild type - 3

Use this information to answer the following questions.

You cross an individual heterozygote for genes A, B and C, with an individual who is homozygote recessive for all three. Assuming independent assortment for all three genes what do you expect to see out of 10,000 offspring?

Remember:

• for all three traits wild type phenotype is dominant to mutant phenotype
• allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A
• allele B is dominant to b; phenotype b = mutant for trait b; phenotype B = wild type for trait B
• allele C is dominant to c; phenotype c = mutant for trait c; phenotype C = wild type for trait C

Select one:

a. Three different phenotypes among the offspring; approximately 3333 offspring of each phenotype.

b. Approximately 156 offspring will have the recessive phenotype for all three traits.

c. Approximately 2963 offspring will be wild type (dominant phenotype for all three traits).

d. Eight different phenotypes among the offspring; approximately 1250 offspring of each phenotype.

Complete the tables below by indicating whether the physical, chemical and biological parameters change with the course of a river.

Please include a valid reason (NO PLAGIARISM!)

What is NOT a major characteristic found in the Kingdom Fungi ?
A. they produce spores B. they have rigid cell walls C. they are multinucleate D. they contain chlorophyll E. None of the previous

1. Why do bacteriophage usually include complex structural features compared to viruses found in humans?

a. Bacteria do not naturally engulf objects/proteins

b. Bacteria have fewer surface proteins for the bacteriophage to bind

c. Human viruses = more evolved than bacteriophage

d. Bacteriophage = more evolved than human viruses

2. circle all that apply: what do most viruses contain or include?

a. DNA

b. Binding proteins

c. An envelope

d. A protein coat

1. After fertilization, all embryos undergo cleavage. In the Xenopus embryo, what is the relationship of the animal-vegetal axis to the plane of the first three cleavages? Describe how cleavage in the chick embryo differs from cleavage in frogs and mice; why do these differences occur?

1. NADH and FADH2 deliver their high energy electrons to

A. glycolysis

b. the electron transport chain

c. oxygen

2. In fermentation, which set of pathways is running, or operating?

A. glycolysis

b. transition

c. Kreb's cycle (also called TCA cycle or citric acid cycle)

d. electron transport chain

e. all of the above

3. As electrons are passed down the electron transport chain, the energy is used to pump ______ across the membrane.

A. B.H+, or hydrogen ions

b. NADH

c. H20

Emphasising the importance of portion control in meal planning. give examples from your daily diet about how you implement this in your day to day eating 

Which statement about DNA replication in eukaryotes is true?

Group of answer choices

Nucleotides are added from beginning to end of one strand, from 5' to 3', and then to the other strand.

Errors that occur during DNA replication are repaired by DNA polymerase.

DNA helicase adds nucleotides with complementary bases to the strand of DNA that is being synthesized.

DNA replication only occurs in somatic cells.

Nucleotides are added to the 5' end of the growing DNA strand.