Question

In: Statistics and Probability

Imagine you are testing for the effects of two experimental drugs (data sets B and C)relative...

Imagine you are testing for the effects of two experimental drugs (data sets B and C)relative to a control group (Data set A) on a physiological variable.

Data set A: 105.51,111.46,104.35,115.27,113.98,119.18,116.45,119.98

Data set B: 93.63,88.90,95.03,86.08,85.86,98.22,105.46,96.50

Data set C: 95.12,97.12,94.08,99.78,101.44,101.27,104.70,103.70

a) Conduct an ANOVA on the data set. Show all calculations, table of results, and state your conclusion.


Please show the calculations.

Solutions

Expert Solution

One Way Analysis of Variance (ANOVA)              

treatment A B C
count, ni = 8 8 8
mean , x̅ i = 113.273 93.71 99.651
std. dev., si = 5.826 6.665 3.886
sample variances, si^2 = 33.947 44.416 15.100
grand mean , x̅̅ = Σni*x̅i/Σni =   102.21
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 122.351 72.271 6.554
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 978.810 578.170 52.429 1609.408825
SS(within ) = SSW = Σ(n-1)s² = 237.629 310.911 105.697 654.2368

no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   24
df within = N-k =   21
  
mean square between groups , MSB = SSB/k-1 =    804.7044
  
mean square within groups , MSW = SSW/N-k =    31.1541
  
F-stat = MSB/MSW =    25.8298

anova table
SS df MS F p-value F-critical
Between: 1609.409 2 804.704 25.830 0.0000 3.467
Within: 654.237 21 31.154
Total: 2263.646 23
α = 0.05

value of test stat=   25.83
p value is    0.0000

   Decision:   p-value<α , reject null hypothesis
      
conclusion :    there is enough evidence of significant mean difference among three treatments  


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