In: Statistics and Probability
magine you are testing for the effects of two experimental drugs (data sets B and C)relative to a control group (Data set A) on a physiological variable.
Data set A: 105.51,111.46,104.35,115.27,113.98,119.18,116.45,119.98
Data set B: 93.63,88.90,95.03,86.08,85.86,98.22,105.46,96.50
Data set C: 95.12,97.12,94.08,99.78,101.44,101.27,104.70,103.70
b) Use the Bonferroni-Holm (regardless of whether part “a” is
significant or not) to examine all pairwise comparisons. Show all
your calculations and state your conclusions
PLEASE SHOW THE CALCULATIONS AND EXPLANATIONS. PLEASE DO NOT USE SPSS
DATA:
A | B | C |
105.51 | 93.63 | 95.12 |
111046 | 88.9 | 97.12 |
104.35 | 95.03 | 9408 |
115.27 | 86.08 | 99.78 |
113.98 | 85.86 | 101.44 |
119.18 | 98.22 | 101.27 |
116.45 | 105.46 | 104.7 |
119.98 | 96.5 | 103.7 |
Bonferroni- Holm test:
Hypothesis
Ho: No Statistical Significance diffrace between A,B and C
Ho: The Statistical Significance diffrace between A,B and C
first i am perfroming the one way ANOVA
SUMMARY | ||||
Groups | Count | Sum | Average | Variance |
A | 8 | 111840.7 | 13980.09 | 1.54E+09 |
B | 8 | 749.68 | 93.71 | 44.41586 |
C | 8 | 10111.13 | 1263.891 | 10828828 |
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 9.49E+08 | 2 | 4.75E+08 | 0.919003 | 0.414373 | 3.4668 |
Within Groups | 1.08E+10 | 21 | 5.16E+08 | |||
Total | 1.18E+10 | 23 |
F-value > P- value
Reject the null Hypothesis in anova between the Group
calultate Bonferroni- Holm test:
alpha = 0.05
t test | Bonferroni | Rank | Holm | ||
A | B | 0.333615 | 0.017 | 2 | 0.025 |
B | C | 0.331586 | 0.017 | 1 | 0.017 |
C | A | 0.376276 | 0.017 | 3 | 0.05 |
frist i am possibel all combination of group find out so three possible combination of above AB, BC, CA then calultate the T-test of each combination, then next calculate Bonferroni value in formula is Given by
Bonferroni = alpha/3
3 becouse the all possible combination group
then Rank decided by the t- test value.
last calultate the Holm value of formula is:
Holm = alpha/(3 -Rank+1)
so compaire the all holm value in t test value so Accept the null hypothesis it's mean's that there is no statistical signifiance diffrance between three drugs A, B, C