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In: Electrical Engineering

A balanced three-phase generator delivers 6.3 kW to a delta-connected load with impedance 13 - j23.4...

A balanced three-phase generator delivers 6.3 kW to a delta-connected load with impedance 13 - j23.4 Ω per phase. The magnitude of the line current I_Lis:

Expert Solution

Given 3 phase delta connected load with per phase impedance 13-23.4j ohm

Total 3 phase power is 6.3KW

3 Vp * Ip * cos¢ = 6.3 KW

¢ is load angle can be calculated from load

13-23.4j

¢ = ( -23.4/ 13)

¢ = 300

Cos ¢ = cos 300 = 0.5

Therefore

Vp* Ip = (6.3/(3*0.5)) = 4.32 KVA ------ equation (1)

Also we know that

Per phase current Ip

= per phase volage ÷ per phase impedance

So magnitude of Ip = √ (161.4121)

= 12.704amp

So magnitude of phase current is 12.704ampere.

Manojponduru answered 2 years ago

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