Question

In: Electrical Engineering

Three balanced 3-phase loads are connected in parallel. Load 1 is Y-connected with an impedance of...

Three balanced 3-phase loads are connected in parallel. Load 1 is Y-connected with an impedance of 400 + j300 ? per phase, load 2 is ?-connected with an impedance of 2400 – j1800 ? per phase, and load 3 is absorbing 172.8 + j2203.2 kVA. The loads are fed from a set of distribution lines with an impedance of 2 + j16 ? per line. The magnitude of the line-to-neutral voltage at the load end of the line is 24?3 kV(rms). Find the total complex power delivered by the generator

Expert Solution

Ans) Given load end line to neutral voltage is

We will first calculate complex power for each load

Load-1

The phase current is given as

Now 3 phase complex power of load 1 is

=============

Load-2

Delta connected phase voltage equals to line voltage i.e

line voltage leads phase voltage by 30 deg for balanced system

The phase current is given as

ow 3 phase complex power of load 2 is

===========

Load 3

Its complex power is given as

=======

Total KVA of load is given as

The total line current into the load is given as

The complex power in the distribution lines is given as

Now total complex power delivered by generator is given as

Manojponduru answered 2 years ago

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