In: Operations Management
The following table lists the components needed to assemble an
end item, lead times (in weeks), and quantities on hand.
Item | Lead Time | Amount on Hand |
Direct Components | |||
End | 3 | 0 | L(2), C(1), K(3) | |||
L | 3 | 12 | B(2), J(3) | |||
C | 4 | 16 | G(2), B(2) | |||
K | 4 | 21 | H(4), B(2) | |||
B | 3 | 26 | ||||
J | 4 | 33 | ||||
G | 4 | 4 | ||||
H | 3 | 0 | ||||
a. If 43 units of the end item are to be
assembled, how many additional units of B are needed?
(Hint: You don’t need to develop an MRP plan.)
Additional units
Answer: 434
Gross Requirement = Total no. units required (irrespective to On hand Inventory)
Net Requirement = Gross Requirement - Amount On Hand
Item B is required for Item L,C and K,
So, to derive the no. of additional unit of B, first we need to find the Gross Requirement of B, which is depend on the Net Requirement of L,C and K
Now Gross Requirement of L,C and K is depend on the end item, because they are direct components to End Item.
Gross Requirement of L = 2* Units of End item to be assembled = 2*43 = 86
Net Requirement of L = Gross Requirement of L - Amount On Hand of L = 86 - 12 =74
Gross Requirement of C = 1* Units of End item to be assembled = 1*43 = 43
Net Requirement of C = Gross Requirement of C- Amount On Hand of C= 43 - 16 =27
Gross Requirement of K = 3* Units of End item to be assembled = 3*43 = 129
Net Requirement of K= Gross Requirement of K- Amount On Hand of K= 129 - 21 = 108
Gross Requirement of B = 2*Net Requirement of L + 2*Net Requirement of C + 2*Net Requirement of K = 2*74 + 2*27 + 2*129 = 148 + 54 + 258 = 460
Net Requirement of B = Gross Requirement of B - Amount on Hand of B = 460 - 26 =434
So, additional 434 units of B are needed.