Design a low rate trickling filter for secondary treatment of sewage generated from 10,000 persons with...

Design a low rate trickling filter for secondary treatment of sewage generated from 10,000 persons with rate of water supply 170 liters per capita per day. The BOD5 after primary treatment is 110 mg/L and BOD5 of final effluent should be 20 mg/L. Consider the following equation, where C = 5.358.

(St/So)=(1)/(1+C((D^0.67)/(QL^0.5))

Now, design a high rate trickling filter for the data given above except effluent BOD5 is 40 mg/l since polishing treatment is provided after high rate trickling filter. Consider a recirculation ratio of 2 and a filter depth of 1.8 m.

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Ally Wells answered 6 months ago

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