Question

In: Chemistry

10. Given the data below, what is ∆Hr for the reaction: FeO   + CO → CO2...

10. Given the data below, what is ∆Hr for the reaction:

FeO   + CO → CO2   +   Fe

                                                                                  ∆Hr

Fe2O3 + 3CO → 2Fe + 3CO2                   –35kJ

3Fe2O3   + CO → CO2 + 2Fe2O4              –70 kJ

Fe3O4 + CO → 3FeO   + CO2                    +45 kJ

Solutions

Expert Solution

Fe2O3 + 3CO → 2Fe + 3CO2...........(1)               ∆Hr = –35kJ

3Fe2O3   + CO → CO2 + 2Fe3O4.......(2)               ∆Hr = –70 kJ

Fe3O4 + CO → 3FeO   + CO2............(3)               ∆Hr = +45 kJ

Multiplying (3) 2

2Fe3O4 +   2CO → 6FeO   +   2CO2............(4)          ∆Hr = +90 kJ

Writing (2) as it is

3Fe2O3   + CO → CO2 + 2Fe3O4.......(2)               ∆Hr = –70 kJ

Multiplying (1) 3 and reversing

6Fe +   9CO2 → 3Fe2O3 +   9CO...........(5)               ∆Hr = +105 kJ

Adding (4) + (2) + (5)

2Fe3O4 + 2CO + 3Fe2O3 + CO + 6Fe + 9CO2 → 6FeO + 2CO2 + CO2 + 2Fe3O4 + 3Fe2O3 + 9CO......∆Hr = +125 kJ

2Fe3O4 + 3CO + 3Fe2O3 + 6Fe + 9CO2 → 6FeO + 3CO2 + 2Fe3O4 + 3Fe2O3 + 9CO......∆Hr = +125 kJ

6Fe + 6CO2 → 6FeO + 6CO......∆Hr = +125 kJ

Reversing the equation

6FeO + 6CO → 6Fe + 6CO2......∆Hr = -125 kJ

Dividing by 6

FeO + CO → Fe + CO2......∆Hr = -20.8 kJ

So answer is -20.8 kJ


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