Question

In: Chemistry

Given the following data: 3FeO(s) + CO2(g) → Fe3O4(s) + CO(g) ΔH° = -18.0 kJ FeO(s)...

Given the following data:

3FeO(s) + CO2(g) → Fe3O4(s) + CO(g) ΔH° = -18.0 kJ

FeO(s) + CO(g) → Fe(s) + CO2(g) ΔH° = -11.0 kJ

Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) ΔH° = -23.0 kJ

Calculate ΔH° for the reaction: 3Fe2O3(s) + CO(g) → 2Fe3O4(s) + CO2(g)

Expert Solution

The reactions have to be rearranged so that summation of the reaction lead to the required reaction

Reaction 1 needs to be multiplied by 2

6FeO(s) + 2CO2(g) → 2Fe3O4(s) + 2CO(g) ΔH° = -36.0 kJ

Reaction 2 needs to be reversed and multiplied by 6 so sign of ΔH° for this reaction changes

6Fe(s) + 6CO2(g) → 6FeO(s) + 6CO(g) ΔH° = 66.0 kJ

Reaction 3 needs to be multiplied by 3

3Fe2O3(s) + 9CO(g) → 6Fe(s) + 9CO2(g) ΔH° = -69.0 kJ

Adding these reactions

6FeO(s) + 2CO2(g) → 2Fe3O4(s) + 2CO(g) ΔH° = -36.0 kJ

6Fe(s) + 6CO2(g) → 6FeO(s) + 6CO(g) ΔH° = 66.0 kJ

3Fe2O3(s) + 9CO(g) → 6Fe(s) + 9CO2(g) ΔH° = -69.0 kJ

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6FeO(s) + 8CO2(g) + 6Fe(s) + 3Fe2O3(s) + 9CO(g) →2Fe3O4(s) + 8CO(g) + 6FeO(s) + 6Fe(s) + 9CO2(g) ΔH° = -39.0 kJ

Cancelling terms between reactants and products we get

3Fe2O3(s) + CO(g) → 2Fe3O4(s) + CO2(g) ΔH° = -39.0 kJ The required reaction with its ΔH°

queen_honey_blossom answered 3 hours ago

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