A clocked sequential circuit has three states, A, B, and C, and one input X. As...

A clocked sequential circuit has three states, A, B, and C, and one input X. As long as the input X is '1', the circuit alternates between the states A and C. If the input X becomes '0' (either in state A or C), the circuit goes to the state B and remain in state B as long as X continues to be '0'. The circuit returns to state A if the input becomes '0' once again and from then on repeats its behavior. Assume that the state assignments are A = 00, B = 01, and C = 10. Answer the following. (1) Draw the state diagram of the circuit. (2) Design the circuit using D-flipflops. *

Expert Solution

Givan Three States - State A , State B , State C

One input - X

(1)State Diagram:

Explanation:As long as the input X is '1', the circuit alternates between the states A and C indicates that for input value X=1 circuit will be altered between A and C.If X=0 them it goes to State B and will be in State B as X continuos to be X=0 So a self loop is drawn for input value X=0.The circuit returns to state A if the input becomes '0' once again and from then on repeats its behavior indicates that repeats for X=0.

(2) Design the circuit using D-flipflops.

Explanation:Dp=X , So Dp is taking input from X , Internal clock (CLK) is taking input from External clock (CLK) , a AND gate is taking inputs and producing outputs.the final outputs are P and Q.

As shown in the table If P=0 and Q=0 it will be in state A , If P=0 and Q=1 it will be in state B , if P=1 and Q=0 it will be in state C.

P	Q	State
0	0	A
0	1	B
1	0	C

venereology answered 1 year ago

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