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A sequential circuit has two JK flip-flops A and B, two inputs r and y, and one output z. The flip-flop input equations and circuit output equation are
\(\begin{aligned} J_{A} &=A^{\prime} x+B^{\prime} y & K_{A}=B x^{\prime} y^{\prime} \\ J_{B} &=A^{\prime} x y & K_{B}=A^{\prime}+B^{\prime} x \\ z &=A^{\prime} x^{\prime}+B^{\prime} y^{\prime} & \end{aligned}\)
(a) Derive the simplified state equations for A and B.
(b) Tabulate the state table.
(c) Draw the state diagram of the çircuit.

(a) Simplified state equations for A and B.
first consider the characteristic equation of any flip-flop:

where Q(t+1) is the next state and Q(t) is current state.
so,

where left hand side A is the next A and right hand side A is current A.

again for B

(b) state table:
| A | B | x | y | A | B | J(A) | K(A) | J(B) | K(B) | Z |
|---|---|---|---|---|---|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 |
| 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 |
| 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 |
| 0 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 0 |
| 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 |
| 0 | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 0 |
| 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 |
| 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 |
| 1 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 0 |
| 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |
(c)
state diagram:
