Two balls connected by a rod as shown in the figure below (Ignore rod’s mass). What is the moment of inertia of the system?

Given :

mX = 400 grams = 0.4kg

mY = 500 grams = 0.5 kg

rX = 0cm = 0m

rY = 30cm = 0.3m

Expert Solution

mX = 400 grams = 0.4kg

mY = 500 grams = 0.5 kg

rX = 0cm = 0m

rY = 30cm = 0.3m

Solution:

I = Mx( rx)^2 + mY( rY)^2

I = (0.4)× (0)^2 + (0.5)× (0.3)^2

I = 0 + 0.045

I = 0.045 kg m^2

Moment of inertia of the system is 0.045kg along the mass M2

To calculate momemt of inertia I=MR^2

M= mass of balls

R-distance between them

Naveen yadav answered 3 years ago

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