In: Physics
Two balls connected by a rod, as shown in the figure below (Ignore rod’s mass). Mass of ball X is 8kg and the mass of ball Y is 5 kg What is the moment of inertia of the system about AB?
Given
The rotation axis is AB
mX = 8kg mass of object x
mY = 5kg mass of object y
rX = 10cm = 0.1 distance from centre object x
rY = 40cm = 0.4m distance from centre object y
Solution:
I = mX rX^2 + mY rY^2
I = (0.8)× (0.1)^2 + (0.8)× (0.4)^2
I = 8 × 10^-3 + 0.128
I = 0.136kg m2.
I = mX rX^2 + mY rY^2
Mx- mass of 1 st object
My- mass of 2 nd object
X,Y- distance from centre for both objects