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In: Chemistry

Why would the actual coefficients of a ferrous ammonium sulfate hexahydrate and the potassium iron oxalate...

Why would the actual coefficients of a ferrous ammonium sulfate hexahydrate and the potassium iron oxalate complex in a balanced chemical equation describing the overall process not be required to compute the predicted weight of the product?

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Ferrous ammonium sulfate, Fe(NH4)2(SO4)2·6H2O, when dissolved in excess oxalic acid, H2C2O4 , various reacton take place are:-

2Fe 2+

=

2Fe 3+ + 2e-

(2e- "lost")

H2O + HO2- + 2e-

=

3OH-

(2e- "gained")

H2O + HO2- + 2Fe 2+

=

2Fe3+ + 3OH-

(net reaction)

FeC2O4 is the source of the Fe 2+ and over all reaction is

Fe(NH4)2(SO4)2· 6H2O + H2C2O4 = FeC2O4(s) + H2SO4 + (NH4)2SO4 + 6H2O(l)

The OH- ion concentration of the solution is high enough so that some of the Fe3+ reacts with OH- to form ferric hydroxide (brown precipitate) asFe3+ + 3OH- = Fe(OH)3(s)

With the addition of more H2C2O4, the Fe(OH)3 dissolves and the soluble complex K3[Fe(C2O4)3]· 3H2O is formed according to: 3K2C2O4 + 2Fe(OH)3(s) +3H2C2O4 = 2K3[Fe(C2O4)3]· 3H2O + 3H2O

The complexity of the series of reactions described in equations 1 - 4 may be greatly simplified by following the Fe2+/Fe3+ ion throughout. One discovers that for every mole of Fe(NH4)2(SO4)2]. 6H2O used as starting material, one mole of K3[Fe(C2O4)3].3H2O will be obtained as the final product.

Fe(NH4)2(SO4)4. 6H2O + H2C2O4

=

FeC2O4 + ......etc.

(Fe2+ = Fe2+)

FeC2O4 + K2C2O4 + H2O2

=

Fe(OH)3(s) + .....etc

(Fe2+ = Fe3+)

Fe(OH)3 + H2O2 + K2C2O4

=

K3[Fe(C2O4)3]·3H2O + ..etc

(Fe3+ = Fe3+)

queen_honey_blossom answered 2 years ago
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