Question

What is the mass of potassium oxalate monohydrate and iron (III) chloride required to synthesize 3g of potassium tris (oxalato)iron (III). water should not be included in equation.
Please include equation and explain in detail. thank you!

Answer 1

potassium oxalate monohydrate: K₂C₂O₄.H₂O

Water should not be included in equation, hence

3 K₂C₂O₄ + FeCl₃ K₃[Fe(C₂O₄)₃] + 3 KCl

In the above reaction  3 mole of K₂C₂O₄ reacts with 1 mole FeCl₃ to produce 1 mole of K₃[Fe(C₂O₄)₃]

Molar mass of K₃[Fe(C₂O₄)₃] = 437.20 g/mol

That is 437.20 g of K₃[Fe(C₂O₄)₃] =  1 mole

3 g of K₃[Fe(C₂O₄)₃] = (1 / 437.20) mole = 0.00229 mole.

Now, 1 mole of K₃[Fe(C₂O₄)₃] produces from 1 mole of FeCl₃.

0.00229 mole of K₃[Fe(C₂O₄)₃] produces from 0.00229 mole of FeCl₃.

Again, 1 mole of K₃[Fe(C₂O₄)₃] produces from 3 mole of K₂C₂O₄.

0.00229 mole of K₃[Fe(C₂O₄)₃] produces from (3 x 0.00229) mole of K₂C₂O₄.

0.00229 mole of K₃[Fe(C₂O₄)₃] produces from 0.00687 mole of K₂C₂O₄.

molar mass of K₂C₂O₄ = 166 g/mol

0.00687 mole of K₂C₂O₄ = (0.00687 x 166) g = 1.140 g

molar mass of FeCl₃ = 162.2 g/mol

0.00687 mole of FeCl₃ = (0.00687 x 162.2) g = 1.114 g

1.140 g of potassium oxalate monohydrate and 1.114 g of iron (III) chloride required to synthesize 3g of potassium tris (oxalato)iron (III).