Question

In: Physics

A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at...

A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at a rate of 2.00 ✕ 104 rev/min.

(a) Find the drill's angular acceleration. rad/s2

(b) Determine the angle (in radians) through which the drill rotates during this period. rad

Expert Solution

Lets,

a) the drill's angular acceleration=

and

where, t=time =3.40 sec

= Angular velocity

because a dentist drill start from rest condition

we can calculate ,

.............................(2)

from equation number (1) and (2)

the drill's angular acceleration is

b) the angle (in radians) through which the drill rotates during this period =

we know that,

the angle (in radians) through which the drill rotates during this period is =37 rad

genius_generous answered 1 hour ago

A dentist's drill starts from rest. After 3.20 s of constant angular acceleration it turns at...

A dentist's drill starts from rest. After 3.20 s of constant angular acceleration it turns at a rate of 3.00 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad

A bicycle starts from rest with a constant acceleration 1 m/s^2. After 5 seconds of having...

A bicycle starts from rest with a constant acceleration 1 m/s^2. After 5 seconds of having started its movement, the brake pin of one of its handlebars, located 5 meters from the ground, is detached. What is the horizontal distance the plug travels from when it comes off until it falls to the ground? Note: Approximate result with only one decimal place

A helicopter propeller blade starts from rest and experiences a constant angular acceleration of 14.0 rad/s2....

A helicopter propeller blade starts from rest and experiences a constant angular acceleration of 14.0 rad/s2. Find the speed of a point on the blade 5.60 m from the axis of rotation when the blade has completed 13 revolutions.

The wheel of an engine starts to rotate from rest with uniform angular acceleration. It accelerates...

The wheel of an engine starts to rotate from rest with uniform angular acceleration. It accelerates angularly for an unknown time (t1) until reaching an angular velocity of 45.13 rad / s, then maintains that angular velocity constant for 37.8 s. The total angle traveled by the wheel in total is 2398.61 rad. a) What is the angular acceleration with which the wheel began to rotate? b) What is the time (t1) that the wheel was accelerating? c) What is...

A wheel, starting from rest, has a constant angular acceleration of 0.7 rad/s^2. In a 0.5-s...

A wheel, starting from rest, has a constant angular acceleration of 0.7 rad/s^2. In a 0.5-s interval, it turns through an angle of 101 rad. How long has the wheel been in motion at the start of this 0.5-s interval?

A wheel, released from rest, is rotating with constant angular acceleration. After 8.0 seconds, its speed...

A wheel, released from rest, is rotating with constant angular acceleration. After 8.0 seconds, its speed reaches to 12 rev/sec (a) what is its angular acceleration? (b) Through what angle has the wheel turned? (c) How many revolutions has it completed in 8.0 second?

A wheel, starting from rest, has a constant angular acceleration of 0.1 rad/s2. In a 2.4-s...

A wheel, starting from rest, has a constant angular acceleration of 0.1 rad/s2. In a 2.4-s interval, it turns through an angle of 120 rad. How long has the wheel been in motion at the start of this 2.4-s interval?

A flywheel with a radius of 0.700m starts from rest and accelerates with a constant angular...

A flywheel with a radius of 0.700m starts from rest and accelerates with a constant angular acceleration of 0.200rad/s2 A. Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 60.0 ?. B. Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 120.0 ?.

A 613-kg elevator starts from rest and moves upward for 2.50 s with constant acceleration until...

A 613-kg elevator starts from rest and moves upward for 2.50 s with constant acceleration until it reaches its cruising speed, 1.63 m/s. (a) What is the average power of the elevator motor during this period? (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.)

A 621-kg elevator starts from rest and moves upward for 3.20 s with constant acceleration until...

A 621-kg elevator starts from rest and moves upward for 3.20 s with constant acceleration until it reaches its cruising speed, 1.65 m/s. (a) What is the average power of the elevator motor during this period? hp (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.) hp