In: Statistics and Probability
Consider the following sets of sample data: A: $30,600, $29,900, $37,500, $29,200, $25,100, $37,400, $26,100, $35,400, $31,500, $34,600, $33,200, $23,100, $25,200, $38,000
B: 89, 78, 85, 81, 76, 97, 70, 73, 88, 76, 99
Step 1 of 2: For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
CV FOR DATA SET A:
CV FOR DATA SET B:
Step 2 of 2:
Which of the above sets of sample data has the smaller spread?
Solution
A )Given that
| x | x2 | 
| 30600 | 936360000 | 
| 29900 | 894010000 | 
| 37500 | 1406250000 | 
| 29200 | 852640000 | 
| 25100 | 630010000 | 
| 37400 | 1398760000 | 
| 26100 | 681210000 | 
| 35400 | 1253160000 | 
| 31500 | 992250000 | 
| 34600 | 1197160000 | 
| 33200 | 1102240000 | 
| 23100 | 533610000 | 
| 25200 | 635040000 | 
| 38000 | 1444000000 | 
 x=436800 | 
 x2=13956700000 | 
The sample mean is 
Mean 
 = (
x
/ n) )
=30600+29900+37500+29200+25100+37400+26100+35400+31500+34600+33200+23100+25200+38000
/14
=436800 /14
=31200
The sample standard is S
  S =
(
 x2 ) - (( 
 x)2 / n ) n -1
=
13956700000-(436800)21413
=
13956700000-1362816000013
=
32854000013
=
25272307.6923
=5027.157
Co-efficient of Variation (Sample) =S / 
 ⋅100%
=5027.157 / 31200⋅100%
=16.11%
Co-efficient of Variation = 16.1%
B ) Given that
| x | x2 | 
| 89 | 7921 | 
| 78 | 6084 | 
| 85 | 7225 | 
| 81 | 6561 | 
| 76 | 5776 | 
| 97 | 9409 | 
| 70 | 4900 | 
| 73 | 5329 | 
| 88 | 7744 | 
| 76 | 5776 | 
| 99 | 9801 | 
 x=912 | 
 x2=76526 | 
The sample mean is 
Mean 
 = (
x
/ n) )
=89+78+85+81+76+97+70+73+88+76+99 /11
=912/11
The sample standard is S
  S =
(
 x2 ) - (( 
 x)2 / n ) n -1
=
76526-(912)211
/10
=
76526-75613.0909/10
=
912.9091/10
=
91.2909
=9.5546
Co-efficient of Variation (Sample) =S/ 
 ⋅100%
=9.5546 /82.9091⋅100%
=11.52%
Co-efficient of Variation = 11.5%
B sets is the above sets of sample data has the smaller spread