In: Statistics and Probability
Consider the following sets of sample data: A: $30,600, $29,900, $37,500, $29,200, $25,100, $37,400, $26,100, $35,400, $31,500, $34,600, $33,200, $23,100, $25,200, $38,000
B: 89, 78, 85, 81, 76, 97, 70, 73, 88, 76, 99
Step 1 of 2: For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
CV FOR DATA SET A:
CV FOR DATA SET B:
Step 2 of 2:
Which of the above sets of sample data has the smaller spread?
Solution
A )Given that
x | x2 |
30600 | 936360000 |
29900 | 894010000 |
37500 | 1406250000 |
29200 | 852640000 |
25100 | 630010000 |
37400 | 1398760000 |
26100 | 681210000 |
35400 | 1253160000 |
31500 | 992250000 |
34600 | 1197160000 |
33200 | 1102240000 |
23100 | 533610000 |
25200 | 635040000 |
38000 | 1444000000 |
x=436800 | x2=13956700000 |
The sample mean is
Mean
= (x
/ n) )
=30600+29900+37500+29200+25100+37400+26100+35400+31500+34600+33200+23100+25200+38000
/14
=436800 /14
=31200
The sample standard is S
S =(
x2 ) - ((
x)2 / n ) n -1
=13956700000-(436800)21413
=13956700000-1362816000013
=32854000013
=25272307.6923
=5027.157
Co-efficient of Variation (Sample) =S /
⋅100%
=5027.157 / 31200⋅100%
=16.11%
Co-efficient of Variation = 16.1%
B ) Given that
x | x2 |
89 | 7921 |
78 | 6084 |
85 | 7225 |
81 | 6561 |
76 | 5776 |
97 | 9409 |
70 | 4900 |
73 | 5329 |
88 | 7744 |
76 | 5776 |
99 | 9801 |
x=912 | x2=76526 |
The sample mean is
Mean
= (x
/ n) )
=89+78+85+81+76+97+70+73+88+76+99 /11
=912/11
The sample standard is S
S =( x2 ) - (( x)2 / n ) n -1
=76526-(912)211
/10
=76526-75613.0909/10
=912.9091/10
=91.2909
=9.5546
Co-efficient of Variation (Sample) =S/
⋅100%
=9.5546 /82.9091⋅100%
=11.52%
Co-efficient of Variation = 11.5%
B sets is the above sets of sample data has the smaller spread