Question

​Previously, 5​% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 5​% today. She randomly selects 130 pregnant mothers and finds that 5 of them smoked 21 or more cigarettes during pregnancy. Test the​ researcher's statement at the α=0.05 level of significance. Identify the correct null and alternative hypotheses.

H0​: p()0.05

H1​: p()0.05

Use technology to find the​ P-value. P-value=() ​(Round to three decimal places as​ needed.)

Is there sufficient evidence to support the​ obstetrician's statement? A.No​, because the​ P-value is greater than α there is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5​%, meaning we do not reject the null hypothesis. B. Yes​, because the​ P-value is greater than α there is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5​%, meaning we do not reject the null hypothesis. C. No​, because the​ P-value is less than α there is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5​%, meaning we reject the null hypothesis. D. Yes​, because the​ P-value is less than α there is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5​%, meaning we reject the null hypothesis.

Answer 1

option A is right

No​, because the​ P-value is greater than α (0.05) there is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 5​%, meaning we do not reject the null hypothesis