Question

In: Statistics and Probability

A newspaper article claimed that more than 42% of women ages 18-33 are mothers. In a...

A newspaper article claimed that more than 42% of women ages 18-33 are mothers. In a random sample of 150 women ages 18-33, 72 were mothers. Use this random sample to test the newspaper article's claim at the 10% significance level.

a: state hypotheses
b: verify conditions that hold
c: calculate the test statistic
d: calculate the p value

Solutions

Expert Solution

Condition required is,

n*p = 150 * 0.43 = 64.5 > 10

And

n*p*q = 150*0.43*0.57 = 36.765 > 10

Conditions satisfied.

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orchestra answered 1 year ago
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