In: Statistics and Probability
A cosmetic company is interested in testing the effectiveness of a new cream for treating skin blemishes. It measured the effectiveness of the new cream compared to the leading cream on the market and a placebo. Data below shows the number of blemishes removed after using the cream for 1 week. Assume two-tailed with an α = .05.
New Cream |
Leading Cream |
Placebo Cream |
81 |
48 |
18 |
32 |
31 |
49 |
42 |
25 |
33 |
62 |
22 |
19 |
37 |
30 |
24 |
44 |
30 |
17 |
38 |
32 |
48 |
47 |
15 |
22 |
49 |
40 |
18 |
41 |
48 |
20 |
Write hypotheses
Determine the Critical value
Compute test statistic
evaluate the null
Null hypothesis : means of all three groups are same
Alternative hypothesis : at least one mean is different
Using Excel, (Data -> Data Analysis -> Anova: Single Factor), we get the following output -
Now,
The value of F statistic = 7.189
and P-value = 0.00314
Since P-value < 0.05, so we reject the null hypothesis and we can conclude that new cream is more effective than the leading cream on the market and a placebo.