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The following reaction was carried out in a 3.75Lreaction vessel at 1100 K: C(s)+H2O(g)?CO(g)+H2(g) If during...

The following reaction was carried out in a 3.75Lreaction vessel at 1100 K:

C(s)+H2O(g)?CO(g)+H2(g)

If during the course of the reaction, the vessel is found to contain 8.25mol of C, 13.3mol of H2O, 3.40mol of CO, and 6.00mol of H2, what is the reaction quotient Q?

Solutions

Expert Solution

To solve this problum first we have to calculate the molarity for each camponent present in 3.75 L.

Molarity (M) :

For Carbon (C),   M= 8.25/3.75 = 2.2 M (as this was solid, we can omit from reactant quotient calculation)

For Water (H2O),   M= 13.3/3.75 = 3.546 M

For Carbonmonoxide (CO),   M= 3.40/3.75 = 0.906 M

For Hydrogen (H2),   M= 6/3.75 = 1.6 M

The Reaction quotient (Q) can be calculated as
Q=Products/Reactants=[CO][H2]/[H2O]= [1.6][0.906] / [3.546]

                                    = 0.4088

                                Q     = 0.4           

queen_honey_blossom answered 2 weeks ago
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