In: Chemistry
Calculate the standard enthalpy change for the following reaction at 25 °C.
H2O(g)+C(graphite)(s) ----> H2(g)+CO(g)
deltaH rxn=_____kJ
deltaH for H2 + ½ O2 = H2O(g) -242 KJ/ mol -----1
deltaH C + ½ O2 = CO -111 KJ/mol---------2
Now arrange the 1st equation and add with eq 2
H2 + ½ O2 = H2O(g) -242 KJ/ mol -----1
H2O(g) = H2 + ½ O2 242 KJ/ mol
C + ½ O2 = CO -111 KJ/mol
H2O(g)+C(graphite)(s) ----> H2(g)+CO(g) +131 KJ/mol