Question

1.The following time estimates are given for an activity: optimistic time = 16 days, most likely time = 24 days and pessimistic time = 40 days.

What is the variance of this activity?

Group of answer choices

A. 9

B. 16

C. 20

D. 24

E. None of these answers are correct

2.The expected waiting time in line is equal to the expected number of customers in line divided by the arrival rate

Group of answer choices

True

False

3. Activities C and D are the immediate predecessors of activity E. The early finish time (EF) of activity C is 35; and the early finish time (EF) of activity D is 42. What is the early start (ES) time of activity E?

Group of answer choices

A. 35

B. 42

C. 77

D. 38.5

E. None of these answers are correct

4. The goal of queueing analysis is to minimize:

Group of answer choices :

A.the sum of customer waiting costs and service costs.

B. the sum of customer waiting time and service time.

C.service costs.

D. customer waiting time.

E. None of the answer choices is correct.

5. All preceding activities have to be completed before work can start on a follower activity.

Group of answer choices

True

False

Answer 1

1.The following time estimates are given for an activity: optimistic time = 16 days, most likely time = 24 days and pessimistic time = 40 days.

What is the variance of this activity?

Given that

Optimistic Time = 16 Days

Most Likely time = 24 Days

Pessimistic Time = 40 Days

Variance = ((pessimistic time - optimistic time)/6)^2=((40-16)/6)^2 =4^2=16

hence, correct answer is 16

2.The expected waiting time in line is equal to the expected number of customers in line divided by the arrival rate

True

3. Activities C and D are the immediate predecessors of activity E. The early finish time (EF) of activity C is 35; and the early finish time (EF) of activity D is 42. What is the early start (ES) time of activity E?

Since C and D are both predecessors of E, then E can start only when both C and D has completed.

So E can start later of 35 and 42. The correct answer is 42

4. The goal of queueing analysis is to minimize:

A. the sum of customer waiting costs and capacity costs