Question

In: Physics

A ski starts from rest and slides down a 24 ∘ incline 95 mlong. Part A...

A ski starts from rest and slides down a 24 ∘ incline 95 mlong.

Part A

If the coefficient of friction is 0.085, what is the ski's speed at the base of the incline?

Express your answer using two significant figures.

Part B

If the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level? Use energy methods.

Express your answer using two significant figures.

Solutions

Expert Solution

A)


FR denotes the frictional force force and FN is the normal force.

If is the coefficient of friction then,

From the diagram it is evident that,

Hence, the force due to friction is

Initially the ski is at rest and has Potential energy only.

Hence, by the principle of conservation of energy,

however the final energy is not only Kinetic energy but also the work done due to friction

If l is the length of the ramp, work done due to friction is

If v is the speed of the ski at the base of the incline, putting the values,

B) Let after coming down the ramp it traverses a distance d

Applying the principle of conservation of energy,


Related Solutions

A ski starts from rest and slides down a 30 ∘ incline 70 m long. A)If...
A ski starts from rest and slides down a 30 ∘ incline 70 m long. A)If the coefficient of friction is 0.075, what is the ski's speed at the base of the incline? B)If the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level? Use energy methods.
A ski starts from rest and slides down a 30 ∘ incline 70 m long. a)...
A ski starts from rest and slides down a 30 ∘ incline 70 m long. a) If the coefficient of friction is 0.095, what is the ski's speed at the base of the incline? b) If the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level? Use energy methods.
An object of mass m1 = 0.435 kg starts from rest at point  and slides down an...
An object of mass m1 = 0.435 kg starts from rest at point  and slides down an incline surface that makes an angle θ = 36.0° with the horizontal as shown. The coefficient of kinetic friction between the object and the incline surface is 0.395. After sliding down a distance d = 5.60 m, it makes a perfectly inelastic collision with an object of mass m2 = 0.650 kg at point . a) Find the speed of m1 at point  just before...
An object of mass m1 = 0.415 kg starts from rest at point  and slides down an...
An object of mass m1 = 0.415 kg starts from rest at point  and slides down an incline surface that makes an angle θ = 36.0° with the horizontal as shown. The coefficient of kinetic friction between the object and the incline surface is 0.455. After sliding down a distance d = 5.80 m, it makes a perfectly inelastic collision with an object of mass m2 = 0.645 kg at point . (a) Find the speed of m1 at point  just before...
A box of mass m1 = 2.0 kg starts from rest and slides down the frictionless...
A box of mass m1 = 2.0 kg starts from rest and slides down the frictionless incline. At point A, the box encounters a (massless) spring of spring constant k. It compresses the spring a distance x = 0.25 m to point B where the speed of the box is 4.4 m/s. The first box is then removed and a second box of mass m2 = 3.0 kg is placed on the same incline at the same initial point and...
Starting from rest, a 4.20-kg block slides 2.30 m down a rough 30.0° incline. The coefficient...
Starting from rest, a 4.20-kg block slides 2.30 m down a rough 30.0° incline. The coefficient of kinetic friction between the block and the incline is μk = 0.436. (a) Determine the work done by the force of gravity. J (b) Determine the work done by the friction force between block and incline. J (c) Determine the work done by the normal force. J (d) Qualitatively, how would the answers change if a shorter ramp at a steeper angle were...
Starting from rest, a 5 kg block slides 2.5 m down a roughly 30 degree incline....
Starting from rest, a 5 kg block slides 2.5 m down a roughly 30 degree incline. the coefficient of kinetic friction between the block and the incline is uk= .436. Determine a) the work done by the force of gravity, b) the work done by the friction force between the rock and the incline and c) the work done by the normal force. d) qualitatively how would answers change if a shorter ramp at a steeper angle were used to...
A sled slides without friction down a small, ice-covered hill. If the sled starts from rest...
A sled slides without friction down a small, ice-covered hill. If the sled starts from rest at the top of the hill, its speed at the bottom is 8.20 m/s. (a) On a second run, the sled starts with a speed of 2.80 m/s at the top. When it reaches the bottom of the hill, is its speed 11.0 m/s, more than 11.0 m/s, or less than 11.0 m/s? more than 11.0 m/s equal to 11.0 m/s less than 11.0...
A ski jumper starts from rest from point A at the top of a hill that...
A ski jumper starts from rest from point A at the top of a hill that is a height h1 above point B at the bottom of the hill. The skier and skis have a combined mass of 80 kg. The skier slides down the hill and then up a ramp and is launched into the air at point C that is a height of 10m above the ground. The skier reaches point C traveling at 42m/s. (a) Is the...
A skier of mass 75kg starts from rest at the top of a friction less incline...
A skier of mass 75kg starts from rest at the top of a friction less incline that is 20.0 m in height. As soon as she touches the bottom of the incline, she encounters a horizontal surface that is 1000 m long and the skier eventually comes to rest. The coefficient of kinetic friction between skier and snow is 0.205. Find the distance the skier covers before coming to rest. Show all work.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT