Question

In: Physics

An object lies 12 cm to the left of a thin double-convex lens of equal radii...

An object lies 12 cm to the left of a thin double-convex lens of equal radii 4.8 cm and n=1.6. The lens forms an image at I1, on the right of the lens. It is desired that the image should be at I2, 2cm to the right of I1. To obtain this result, a thin lens of focal length +/- 12 cm is placed between the first lens and I1. Deduce what kind of lens is needed, and find the distance of the second lens from the first. Draw a ray diagram.

Solutions

Expert Solution


Related Solutions

A small object is placed to the left of a convex lens and on its optical...
A small object is placed to the left of a convex lens and on its optical axis. The object is 50 cm from the lens, which has a focal length of 15 cm. Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) _____ cm from the lens Describe the image. (Select all that apply.) real ____ Virtual ___ upright ____ Inverted ___ enlarged ___ Reduced ___ on the left side of...
Consider a double convex lens with a focal length of 35 cm. If a marble is...
Consider a double convex lens with a focal length of 35 cm. If a marble is placed 85 cm from the lens, what is the image distance? Enter your answer in cm.
An object is 15.2 cm to the left of a lens with a focal length of...
An object is 15.2 cm to the left of a lens with a focal length of 10.2 cm. A second lens of focal length 11.8 cm is 39.27 cm to the right of the first lens. The height of the object of is 2.1 cm. What is the location of the final image with respect to the second lens? What is the height of the image?
An object is located to the left of a convex lens whose focal length is f=34...
An object is located to the left of a convex lens whose focal length is f=34 cm. The magnification (m) produced by the lens is 4.0. Find an expression for magnification in terms of “f” and object distance (do). To increase the magnification to 5.0, calculate the distance through which the object should be moved. Also explain your result with free hand ray diagram. At what position of the object the magnification becomes infinity?
1. Consider a convex lens with a focal length of 5.50 cm. An object is located...
1. Consider a convex lens with a focal length of 5.50 cm. An object is located at 13.50 cm. The object is 6.00 cm tall. Draw the ray diagram to scale. Determine the image distance, the height of the image, the magnification and the characteristices of the image. Pay attention to the sign conventions and units. 2. White light shines through a diffraction grating with 7300 lines per cm. Make a table of diffraction angles for m = 1, 2,...
A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal...
A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal length of -3.1 cm. A converging lens with a focal length of 4.6 cm is distance d to the right of the first lens. a) For what value of d is the image at infinity? b) What is the angular size of the image as seen by looking through the converging lens? ?c) What is the angular magnification of this two-lens magnifier?
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens...
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens having a focal length of 25.8 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position :__________ cm...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of focal length 8.95 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm  ---Select--- behind the...
An object is located at a distance of 5 cm from a thin convergent lens of...
An object is located at a distance of 5 cm from a thin convergent lens of focal length 33 mm. The image produced has the following characteristics:
A symmetric, double-convex, thin lens made of glass with index of refraction 1.52 has a focal...
A symmetric, double-convex, thin lens made of glass with index of refraction 1.52 has a focal length in air of 40.0 cm. The lens is sealed into an opening in the left-hand end of a tank filled with water. At the right-hand end of the tank, opposite the lens, is a plane mirror 90.0 cm from the lens. The index of refraction of the water is 4/3. 1.Find the position of the image formed by the lens-water-mirror system of a...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT