A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of...

A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of focal length 8.95 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.

position
Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm ---Select--- behind the second lens in front of the second lens height
Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm

Is the image inverted or upright?

uprightinverted

Is the image real or virtual?

realvirtual

(b)

What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position?

distance cmdirection ---Select--- to the left to the right

Solutions

Expert Solution

genius_generous answered 1 year ago

Next > < Previous

Related Solutions

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal...

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 9.00 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.

An object 2.00 cm high is placed 30.8 cm to the left of a converging lens...

An object 2.00 cm high is placed 30.8 cm to the left of a converging lens having a focal length of 25.8 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position :__________ cm...

An object is placed 49 cm to the left of a converging lens of focal length...

An object is placed 49 cm to the left of a converging lens of focal length 21 cm. A diverging lens of focal length − 29 cm is located 10.3 cm to the right of the first lens. (Consider the lenses as thin lenses). a) Where is the final image with respect to the second lens? b)What is the linear magnification of the final image?

An object 5 centimeters high is placed 15 cm in front of a converging lens with...

An object 5 centimeters high is placed 15 cm in front of a converging lens with focal length 5 cm. Using graph paper (turn the paper so that the long side is horizontal) and a straight edge, draw appropriate rays to locate the image. Chose a scale (tell me what it is!) such that the lens is in the center of the page and the object is near the left side of the page a. Is the image real or...

An object 20 cm tall is placed at 50 cm in front of a converging lens...

An object 20 cm tall is placed at 50 cm in front of a converging lens with a focal length of 5 cm. A. Find the location and nature of the image. B. Draw the diagram

A converging lens has a focal length of 15 cm. If an object is placed at...

A converging lens has a focal length of 15 cm. If an object is placed at a distance of 5 cm from the lens, a. find the image position d i = _____ cm (include sign +/-) b. find the magnification M = _____(include sign +/-) c. characterize the resulting image. ________(real or virtual) ________(enlarged or reduced) ________(upright or inverted)

a) The focal length of a converging lens is 35 cm. An object is placed 100...

a) The focal length of a converging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. b) The focal length of a converging lens is 35 cm. An object is placed 30 cm in front of the lens. Describe the image. c) The focal length of a diverging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. d) The focal length of...

A 2 cm high object is positioned 5 cm to the right of a converging lens...

A 2 cm high object is positioned 5 cm to the right of a converging lens (f= +3 cm). A diverging lens (f= -15 cm) is located 10 cm to the left of the converging lens. Determine its location and if the final image is inverted and virtual. Show ray tracing diagram to prove your answer.

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal...

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal length of 4.0cm . A diverging lens, of focal length -7.4cm, is 14cm to the right of the first lens. Find the position of the final image. s2` = -5.7 cm Find the size of the final image. h2` = ? Find the orientation of the final image. a) real, upright b) real, inverted c) virtual, upright d) virtual, inverted

An object is placed 66.0 cm from a screen. (a) Where should a converging lens of...

An object is placed 66.0 cm from a screen. (a) Where should a converging lens of focal length 7.5 cm be placed to form a clear image on the screen? (Give your answer to at least one decimal place.) shorter distance cm from the screen farther distance cm from the screen (b) Find the magnification of the lens. magnification if placed at the shorter distance magnification if placed at the farther distance

Subjects