Question

write a c code to test the 3rd and 8th bit set or not (1 or 0).
if both set, display "true";
if either one set, display "half true";
if neither set, display "false".

Answer 1

//Always remember bit order starts from 0.

#include <stdio.h>

int main()
{
    int num, n, bitStatus,bitStatus1; //integer declaration

    /* Input number from user */
    printf("Enter any number: ");
    scanf("%d", &num);

    /* Right shift num,3 times and perform bitwise AND with 1 */
    bitStatus = (num >> 3) & 1;
      /* Right shift num,8 times and perform bitwise AND with 1 */
     bitStatus1 = (num >> 8) & 1;
if(bitStatus==1 && bitStatus1==1){
    printf("true");
}

else if(bitStatus==1 || bitStatus1==1){
    printf("half true");
}
else{printf("false");
}
    return 0;

}