In: Physics
given
V1 = 0.240 m^3
n = 10.3 mol
T1 = 19 C = 19 + 273 = 292 K
a) use, P1*V1 = n*R*T1
P1 = n*R*T1/V1
= 10.3*8.314*292/0.24
= 1.042*10^5 pa <<<<<<<--------------Answer
b) internal energy, U1 = (3/2)*n*R*T1
= (3/2)*10.3*8.314*292
= 3.75*10^4 J <<<<<<<<<<------------Answer
c) Workdone by the gas, W = P1*(V2 - V1)
= 1.042*10^5*(1 - 0.24)
= 7.92*10^4 J <<<<<<<<----------------Answer
d) at constant pressure, V/T = constant
so, V1/T1 = V2/T2
T2 = T1*(V2/V1)
= 292*(1/0.24)
= 1217 K (or) 944 C <<<<<<<<-------------Answer
e) U2 = (3/2)*n*R*T2
= (3/2)*10.3*8.314*1217
= 1.56*10^5 J <<<<<<<<<---------------Answer
f) delta_U = U2 - U1
= 1.56*10^5 - 7.92*10^4
= 7.68*10^4 J <<<<<<<---------Answer
h) thermal energy must be transferred to the gas during the constant pressure expansion.
i) Q = delta_U + W
= 7.68*10^4 + 7.92*10^4
= 1.56*10^5 J <<<<<<<<<------------Answer