In: Chemistry
A sample of gas mixture from a neon sign contains 4.95x10^-2 mol Ne and 3.07x10^-2 mol Kr . What are the mass percentages of Ne and Kr in the gas mixture?
Mass percentages of Ne = %
Mass percentages of Kr = %
mass of Ne = no of moles * gram atomic mass
= 4.95*10^-2 * 20.1797 = 0.9988g
mass of Kr = no of moles * gram atomic mass
= 3.07*10^-2 *83.798 = 2.573g
Mass percentages of Ne % = 0.9988*100/0.9988+2.573
= 0.9988*100/3.5718 = 27.96%
Mass percentages of Kr% = 2.573*100/0.9988+2.573
= 2.573*100/3.5718 = 72.04%