In: Chemistry
A cylinder with a moveable piston contains 0.553 mol of gas and has a volume of 256 mL .
What will its volume be if an additional 0.246 mol of gas is added to the cylinder? (Assume constant temperature and pressure.)
V1 = 256 ml , n1 = 0.553 mole
V2 = ? , n2 = ( 0.553 + 0.246 ) mole = 0.799 mol
PV = nRT ( P, V and R are constants )
therefore V is proportional to the n = no of moles of gas
V1 / V2 = n1 / n2 ===> V2 = ( n2 / n1 ) x V1
= ( 0.799 mol / 0. 553 mol ) x 256 ml
= 369.88 ml