Question

In: Chemistry

A gas cylinder contains 2.30 mol He, 1.35 mol Ne, and 1.75 mol Ar. If the...

A gas cylinder contains 2.30 mol He, 1.35 mol Ne, and 1.75 mol Ar. If the total pressure in the cylinder is 2290 mmHg, what is the partial pressure of each of the components? Assume constant temperature.

P(He) = ?

P(Ne) = ?

P (Ar) = ?

Expert Solution

no of moles of He nHe = 2.3 moles

no of moles of Ne n Ne = 1.35 moles

no of moles of Ar n Ar = 1.75 moles

mole fraction of He (X He) = n He/n He + n Ne + n Ar

= 2.3/2.3+1.35 + 1.75

= 2.3/5.4 = 0.426

mole fraction of Ne (X Ne) = n Ne/n He + n Ne + n Ar

= 1.35/2.3+1.35 + 1.75

= 1.35/5.4 = 0.25

mole fraction of Ar (X Ar) = n Ar/n He + n Ne + n Ar

= 1.75/2.3+1.35 + 1.75

= 1.75/5.4 = 0.324

total pressure (PT) = 2290mmHg

partial pressure of He (PHe) = X He* PT

= 0.426*2290 = 975.54mmHg

partial pressure of Ne (PNe) = X Ne* PT

= 0.25*2290 = 572.5mmHg

partial pressure of Ar (PAr) = X Ar* PT

= 0.324*2290 = 741.96mmHg

queen_honey_blossom answered 1 year ago

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