C6H14(l) + Br2(l) + light → C6H13Br(l) + HBr(g) How do I explain this reaction?

Solutions

Expert Solution

the reaction is a radical substitution reaction. it is also a chain reaction(self propagating reaction)

Brown bromine disappears, while hydrogen bromide and bromohexane are formed:

C6H14(l) + Br2(l) -----light----> C6H13Br(l) + HBr(g)

The only observable change you will be a change in colour. Bromohexane which is the final product of the reaction is colourless. so as the reaction proceeds there will be gradual loss of the reddish brown colour until the solution turns colourless.

a completely colourless solution will result if the the Hexane does not run out before the completion of the reaction. If the amount of hexane is limited the end product will not be completely colourless as it will contain excess bromine*( which is responsible for the reddish brown colouration).

in other words a totally colourless solution will result if all the bromine is consumed in the course of the reaction.

queen_honey_blossom answered 1 week ago

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