Problem 1: For the reaction 2CH3OH(l) + 3O2(g) = 2CO2 + 4H2O(l) I calculated that the...

Problem 1: For the reaction 2CH₃OH_(l) + 3O₂_(g) = 2CO₂ + 4H₂O_(l) I calculated that the change in molar entropy of the system is 313.7 Joules/(moles*kelvin). The question then asked what is the entropy change of the system when 2.35 moles of O₂ react. I multiplied 313.7 Joules/(moles*kelvin) by 2.35 moles of O₂ and also divided by 3 moles of O₂ because of the "3" coefficient, and got 246 Joules/kelvin and I just want to make sure that last part was correct. Specifically, was I correct to both multiply by 2.35 and divide by 3.

Problem 2: Very similar problem. For the reaction H_2(g) + F_2(g) = 2HF_(g) I calculated that the change in molar entropy of the surroundings is 1,819 Joules/(moles*kelvin). The question then asked to calculate the entropy change of the surroundings when 2.15 moles of H_2(g) react, so I multiplied 1,819 Joules/(moles*kelvin) by 2.15 moles of H₂_(g) and then divided by 1 moles of H_2(g) since the coefficient is "1" and got 3,911 Joules/kelvin, and I just want to make sure this last part is correct. Specifically, was I correct to multiply by 2.15 and then divide by 1

Solutions

Expert Solution

Q1-According to the 3rd law of thermodynamics, entropy change is calculated by substracting the total energy of reactants from the total energy of products.

- The total energy of each reactant and product is directly proportional to their no of moles

- As the no of moles increases or decreases in the reactant side, then the of mole changes in product side also, so as total energy associated with them increases or decreases simultaneously and respectively . It is also multiple to their coefficient

Hence for 2CH3OH + 3O2 = 2CO2 + 2H2O total entropy change= 313.7 joules/mole*kelvin

Then (2.35*2/3) CH3OH + (3*2.35/3) O2 = (2*2.35/3) CO2 + (2*2.35/3) H2O total entropy change = 313.7*2.35/3 = 245.73 or 246

Hence if you calculate the energy values for all the molecules in the 2nd equation, then total entropy change will be 246 joules/mole*kelvin

So Problem 1 is correct

2- In the same way, If H2 + F2 = 2HF total entropy change = 1819 joule/kelvin

then 2.15 H2 + 2.15 F2 = 2*2.15 HF total entropy change = 2.15* 1819 = 3910.85 or 3911 joule/kelvin

So problem 2 also correct

queen_honey_blossom answered 1 year ago

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