Question

In: Chemistry

The reaction H2(g) + Br2(g) 2HBr(g) has Kc = 2.0 x 109 at 25 °C. If...

The reaction H2(g) + Br2(g) 2HBr(g) has Kc = 2.0 x 109 at 25 °C. If 0.100 mol of H2 and 0.100 mol of Br2 were placed in a 10.0 L container and allowed to react, what would all the equilibrium concentrations be at 25 °C?

Solutions

Expert Solution

                     H2(g) + Br2(g)-------- 2HBr(g)

Initial             0.1       0.1                0

Final            (0.1-x)   (0.1-x)           2x

Taking square root both sides we get

Concentration of HBr = 2x = 0.199998

Concentration of H2 = concentration of Br2 = 0.00001


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