In: Chemistry
The reaction H2(g) + Br2(g) 2HBr(g) has Kc = 2.0 x 109 at 25 °C. If 0.100 mol of H2 and 0.100 mol of Br2 were placed in a 10.0 L container and allowed to react, what would all the equilibrium concentrations be at 25 °C?
H2(g) + Br2(g)-------- 2HBr(g)
Initial 0.1 0.1 0
Final (0.1-x) (0.1-x) 2x
Taking square root both sides we get
Concentration of HBr = 2x = 0.199998
Concentration of H2 = concentration of Br2 = 0.00001