In: Chemistry
A reaction of 59.5 g of Na and 48.7 g of Br2 yields 57.1 g of NaBr. What is the percent yield?
reaction is 2Na + Br = 2NaBr
now weight of Na = 59.5gm
M.Wt of Na = 23
moles of Na = 59.5/23 = 2.58
weight of Br2 = 48.7 g
M.Wt of Br2 =159
moles of Br2 = 48.7/159 = 0.306
0.306 mole of Br2 is reacting with 2.58 moles of sodium metal
theartical yield of any reaction = M.Wt of product x weight of starting material/M.Wt of starting material
= 102.89 x59.5/23
= 266 gm
% Yield = isolated yield x 100/thearical yield
= 57.1 x 100/266
= 21.466%