In: Math
An anthropologist records the heights (in inches) of ten fathers and their sons. Use the Spearman rank correlation test to analyze the results.
Son's Height | Father's Height |
---|---|
64 | 64 |
57 | 66 |
52 | 79 |
50 | 78 |
41 | 77 |
40 | 90 |
66 | 81 |
78 | 80 |
58 | 61 |
56 | 82 |
Step 1 of 2:
Find the value of the correlation coefficient to test for an association between the heights of the fathers and the heights of their sons. Round your answer to four decimal places, if necessary.
( X) | ( Y) | X^2 | Y^2 | X*Y |
64 | 64 | 4096 | 4096 | 4096 |
57 | 66 | 3249 | 4356 | 3762 |
52 | 79 | 2704 | 6241 | 4108 |
50 | 78 | 2500 | 6084 | 3900 |
41 | 77 | 1681 | 5929 | 3157 |
40 | 90 | 1600 | 8100 | 3600 |
66 | 81 | 4356 | 6561 | 5346 |
78 | 80 | 6084 | 6400 | 6240 |
58 | 61 | 3364 | 3721 | 3538 |
56 | 82 | 3136 | 6724 | 4592 |
calculation procedure for correlation
sum of (x) = 562
sum of (y) = 758
sum of (x^2) = 32770
sum of (y^2) = 58212
sum of (x*y) = 42339
to calculate value of r( x,y) = co variance ( x,y ) / sd (x) * sd (y)
co variance ( x,y ) = [ sum (x*y - N *(sum (x/N) * (sum (y/N) ]/n-1
= 42339 - [ 10 * (562/10) * (758/10) ]/10- 1
= -26.06
and now to calculate r( x,y) = -26.06/ (SQRT(1/10*42339-(1/10*562)^2) ) * ( SQRT(1/10*42339-(1/10*758)^2)
=-26.06 / (10.8885*8.6925)
=-0.2753
value of correlation is =-0.2753
coefficient of determination = r^2 = 0.0758
properties of correlation
1. If r = 1 Correlation is called Perfect Positive Correlation
2. If r = -1 Correlation is called Perfect Negative Correlation
3. If r = 0 Correlation is called Zero Correlation
& with above we conclude that correlation ( r ) is = -0.2753< 0, negative correlation