In: Chemistry
Calculate the change in Gibbs free energy for each of the following sets of ΔH∘rxn, ΔS∘rxn, and T. (Assume that all reactants and products are in their standard states.)
Part A ΔH∘rxn=−84kJ, ΔS∘rxn=−157J/K, T=302K Express your answer as an integer.
Part B ΔH∘rxn=−84kJ, ΔS∘rxn=−157J/K, T=860K Express your answer as an integer.
Part C ΔH∘rxn=84kJ, ΔS∘rxn=−157J/K, T=302K Express your answer as an integer.
Part D ΔH∘rxn=−84kJ, ΔS∘rxn=157J/K, T=398K Express your answer as an integer.
A)
deltaH = -84.0KJ/mol
deltaS = -157J/mol.K
= -0.157 KJ/mol.K
T = 302 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
deltaG = -84.0 - 302.0 * -0.157
deltaG = -36.586 KJ/mol
Answer: -37 KJ/mol
B)
deltaH = -84.0KJ/mol
deltaS = -157J/mol.K
= -0.157 KJ/mol.K
T = 860 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
deltaG = -84.0 - 860.0 * -0.157
deltaG = 51.02 KJ/mol
Answer: 51 KJ/mol
C)
deltaH = 84.0KJ/mol
deltaS = -157J/mol.K
= -0.157 KJ/mol.K
T = 302 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
deltaG = 84.0 - 302.0 * -0.157
deltaG = 131.414 KJ/mol
Answer: 131 KJ/mol
D)
deltaH = -84.0KJ/mol
deltaS = 157J/mol.K
= 0.157 KJ/mol.K
T = 398 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
deltaG = -84.0 - 398.0 * 0.157
deltaG = -146.486 KJ/mol
Answer: -146 KJ/mol