In: Chemistry
Calculate the change in Gibbs free energy for each of the following sets of ΔH∘rxn, ΔS∘rxn, and T.
ΔH∘rxn=− 132 kJ ; ΔS∘rxn= 260 J/K ; T= 310 K
ΔH∘rxn= 132 kJ ; ΔS∘rxn=− 260 J/K ; T= 310 K
ΔH∘rxn=− 132 kJ ; ΔS∘rxn=− 260 J/K ; T= 310 K
ΔH∘rxn=− 132 kJ ; ΔS∘rxn=− 260 J/K ; T= 563 K
ΔH∘rxn=− 132 kJ ; ΔS∘rxn= 260 J/K = 0.26KJ/K; T= 310 K
ΔG∘rxn = ΔH∘rxn - TΔS∘rxn
= -132-310*0.26 = -212.6KJ
ΔH∘rxn= 132 kJ ; ΔS∘rxn=− 260 J/K = -0.26KJ/K; T= 310 K
ΔG∘rxn = ΔH∘rxn - TΔS∘rxn
= 132-310*-0.26 =212.6KJ
ΔH∘rxn=− 132 kJ ; ΔS∘rxn=− 260 J/K = -0.26KJ/K ; T= 310 K
ΔG∘rxn = ΔH∘rxn - TΔS∘rxn
= -132-310*-0.26 = -51.4KJ
ΔH∘rxn=− 132 kJ ; ΔS∘rxn=− 260 J/K = -0.26KJ/K; T= 563 K
ΔG∘rxn = ΔH∘rxn - TΔS∘rxn
= -132-563*-0.26 = 14.38KJ