You've decided to build a radio to listen to your favourite FM radio station, which broadcasts at 102.9 MHz. For the tuner, you'll be using an RLC circuit, but the only inductor you happen to have on hand has a value of 0.870 μH.

Unfortunately, there's another radio station — which you don't want to listen to — at a nearby frequency of 103.3 MHz. To prevent any interference from this 103.3 MHz radio station, you want the peak current from it to be no more than 0.160% of the peak current from your favourite 102.9 MHz station. What value of resistor should you use in your RLC circuit? (Assume the two stations have the same strength.)

Hint:You'll have to first calculate the value of the capacitor so that the radio tunes to 102.9 MHz.

CHAPTER 15(13.)

On January 1, 2018, Nath-Langstrom Services, Inc., a computer software training firm, leased several computers under a two-year operating lease agreement from ComputerWorld Leasing, which routinely finances equipment for other firms at an annual interest rate of 4%. The contract calls for four rent payments of $15,500 each, payable semiannually on June 30 and December 31 each year. The computers were acquired by ComputerWorld at a cost of $101,000 and were expected to have a useful life of Five years with no residual value. Both firms record amortization and depreciation semi-annually. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)

Required:
Prepare the appropriate entries for both the lessee and the lessor from the beginning of the lease through the end of 2018. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round your intermediate calculations to the nearest whole dollar amount.)

• Record the lease revenue received by ComputerWorld Leasing.
• Record the Depreciation expense for ComputerWorld Leasing.
• Record the lease revenue received by ComputerWorld Leasing.
• Record the Depreciation expense for ComputerWorld Leasing.

All the answers must be in Binary format. As always please show all your work.

9.75 + 0.5625

125.125 * 12.0625

An ice cube of mass 11.4 g and initial temperature -6.0°C is held in your hand such that the water resulting from the melted ice reaches the temperature of your hand, 36.2°C. In order to accomplish this, how much heat (in kJ) must be absorbed by the ice cube and resulting water? Assume that all the water remains in your hand. Hint: Tables 14.1 and 14.2 in your textbook will be useful here.

Detail design a gear reducer that would meet (at a minimum) the following design specification:

• Power to be delivered: 40 hp
• Input speed: 1750 rpm
• Output speed: 40–44 rev/min
• Usually low shock levels, occasional moderate shock
• Input and output shafts extend 4 in outside gearbox
• Maximum gearbox size: 18-in x 18-in base, 36-in height
• Output shaft and input shaft in-line
• Connection to a roller and conveyor via a chain drive

Other than the reducer design, design the intermediate and main shafts, including complete specification of the gears, bearings, keys, retaining rings, and shaft.

The Cherry Kool Aid dispensed from the burette was prepared as per the package instructions. The suggested serving size of Kool Aid is 8.0 ounces. How many moles and grams of red 40 (MW=496.42g/mol) are found in a serving fo Cherry Kool Aid? ( HInt: Use the concentration of undiluted Kool Aid you determined in the lab= 0.092mM )

Calculate [OH?] and pH for strong base solution formed by mixing 15.0mL of 1.00

Single inheritance

Given two integer numbers N1 and N2, create a class 'ProblemSolution' with following characteristics.

1. Must extend a 'Base' class.
2. Create a method 'solution' with two integer parameters (N1 and N2) and long return type.
3. The 'solution' method should call the addition and subtraction methods of 'Base' class and return multiplication of returned results of addition and subtraction method.

Result = (N1 + N2) * (N1 - N2)

What is inheritance?
Inheritance is a mechanism in which one object acquires all the properties and behaviors of the parent object.
Reference: https://www.tutorialspoint.com/cplusplus/cpp_inheritance.htm

Input
    50
    10

Output
    2400

Given:

#include <iostream>
using namespace std;

// Base class
class Base {
public:
int addition(int N1, int N2) {
int result = N1 + N2;
return result;
}
  
int subtraction(int N1, int N2) {
int result = N1 - N2;
return result;
}
  

};

   //write your code here

int main() {
int N1;
int N2;
cin >> N1;
cin >> N2;
ProblemSolution problemSolution;
cout << problemSolution.solution(N1,N2);
return 0;
}

C++

Must Run:

Both numbers being 0

1 negative and 1 positive number

both negative numbers

Large numbers

Is there enough evidence in the data that population average price of diamond for color “E” is more than 1500?

Solve in R using the t test.

Homework 4

Put all home works together and use methods to simplify code. Also expand to have preferences and budget for wall coverings the way that was done for floor options

Use separate Methods to calculate the change for each the Door, Window and Bookcase (Hint – you may want to use 2 methods for the book case effects since one is floor and other is wall).

The user shall input the dimensions of the room and the eventual output will be how the walls and flooring is done and how much budget is left.

The user will input the number of doors, windows, and bookcases and the dimensions of each which will be used to adjust the total wall and floor space needed to be covered. The system will output the square feet of wall and floor after adjustments.

The user will be asked for his budget for the walls and if he has a preference for the type of material for the wall. The system will accept as input the costs for the different wall coverings and determine which wall covering the user can afford – being either his preference or the most expensive if he does not have a preference. It’s also possible the user can not afford any wall coverings. The budget left after the wall covering is kept for how much money is left.

The system will output the initial budget for walls, the selected option and cost and what is left in the budget for walls.

The same process will work for floor coverings with the same output for flooring.

YOU also have COST OPTIONS FOR WALLS, A USER PREFERENCE AND A BUDGET, YOU WILL DO THE SAME FOR THE WALL. SAME RULES APPLY – IF 0 THEN JUST PICK MOST EXPENSIVE, IF PREFERENCE GIVE PREFERENCE IF CAN AFFORD, IF NOT GIVE WHAT CAN AFFORD.

There are four options for wall cover (Ceramic Tile = 1; Paneling = 2, Wallpaper = 3; and paint = 4) each with a cost per square foot The program will ask for input and read in the budget in dollars and cents, the cost per square foot for each of the different wall options and also ask for which one the customer prefers where 0 means the customer does not care and 1-4 if they have a specific preference.

Output the users preference, their budget, if they got their preference, and what they did get. Also how much budget is left.

You will be graded on how well you map this to methods and how good the comments are explaining what the program does.

Use the following for data (it is the same as HW 3 so you should get the same selection answers for flooring as you get there.

·         First renovation project (THREE DOORS, ONE BOOKSHELF, NO WINDOWS)

o    Room is 12 feet long, 12 feet wide, and 12 feet high

o    Door 1 is 2 feet wide by 10 feet high

o    Door 2 is 3 feet wide by 5 feet high

o    Door 3 is 3 feet wide by 5 feet high

o    Bookshelf is 8 feet long by 10 feet high by 2 feet deep

o    No windows

·         Second renovation project (3 WINDOWS, 2 BOOKSHELFS, NO DOORS)

o    Room is 24 feet long, 12 feet wide, and 8 feet high

o    Window 1 is 2 feet wide by 6 feet high

o    Window 2 is 3 feet wide by 5 feet high

o    Window 3 is 8 feet wide by 5 feet high

o    Bookshelf 1 is 8 feet long by 6 feet high by 3 feet deep

o    Bookshelf 2 is 3 feet long by 6 feet high by 2 feet deep

o    No doors

·         Third renovation project (ONE DOOR, 2 WINDOWSS, ONE BOOKSHELF)

o    Room is 12.75 feet long, 11.25 feet wide, and 12 feet high

o    Door is 1.95 feet wide by 10 feet high

o    Window 1 is 2.5 feet wide by 5 feet high

o    Window 2 is 6.8 feet wide by 7.2 feet high

o    Bookshelf is 8 feet long by 6 feet high by 3 feet deep

For Flooring use:

Tile= $4.00 /sq ft; Wood = $3.00/ sq ft; Carpet = $2.00/ sq ft and linoleum = $1.00/sq ft).

Use the following as the budget and preference:

There are four options for wall cover (Ceramic Tile = 1; Paneling = 2, Wallpaper = 3; and paint = 4) each with a cost per square foot

For all three test renovation projects use Tile= $4.00 /sq ft; Paneling = $3.00/ sq ft; Wallpaper = $2.00/ sq ft and paint = $1.00/sq ft).

Use the following as the budget and preference:

hw 3

package lab;

import static java.lang.System.*;
import java.util.Scanner;
// Renovation Project
public class hw3 {
{
}
public static void main(String args[]) {
double rheight, rwidth, rlength; //room height,width and length variabe
int numberOfDoors,numberOfWindows,numberOfBookCases=0;
double dheight=0, dwidth=0; //door height and width variable
double w1height, w1width;//window1 height and width variable
//double w2height, w2width;//window2 height and width variable
double bheight, bwidth, blength;//bookshelf height ,length and width variable
double paintArea, carpentArea, floorArea;
double paintCost, carpentCost = 0, floorCost, budget;
int preferences = 0;
String flooring = "";
Scanner s = new Scanner(System.in);
out.print("Enter the Room height : ");
rheight = s.nextDouble();
out.print("\nEnter the Room width : ");
rwidth = s.nextDouble();
out.print("\nEnter the Room length : ");
rlength = s.nextDouble();
//Taking number of Rooms as input
out.print("Enter the Number of Doors: ");
numberOfDoors=s.nextInt();
double totalDoorSize=0;
//calculate total size of doors by iterating over number of doors
for(int i=1;i<=numberOfDoors;i++){
out.print("\nEnter the Door"+i+" height : ");
dheight = s.nextDouble();
out.print("\nEnter the Door"+i+" width : ");
dwidth = s.nextDouble();
totalDoorSize=totalDoorSize+(dheight*dwidth);
}
//Taking number of Windows as input
out.print("Enter the Number of Windows: ");
numberOfWindows=s.nextInt();
double totalWindowSize=0;
//calculate total size of doors by iterating over number of windows
for(int i=1;i<=numberOfWindows;i++){
out.print("\nEnter the Window"+i+" height : ");
w1height = s.nextDouble();
out.print("\nEnter the Window"+i+" width : ");
w1width = s.nextDouble();
totalWindowSize=totalWindowSize+(w1height*w1width);
}
//Taking number of Bookcases as input
out.print("Enter the Number of Bookcases: ");
numberOfBookCases=s.nextInt();
double totalBookCasesCarpetArea=0,totalBookCasesPaintArea=0;
//calculate total size of doors by iterating over number of bookcase
for(int i=1;i<=numberOfBookCases;i++){
out.print("\nEnter the bookshelf"+i+" height : ");
bheight = s.nextDouble();
out.print("\nEnter the bookshelf"+i+" width : ");
bwidth = s.nextDouble();
out.print("\nEnter the bookshelf"+i+" length : ");
blength = s.nextDouble();
totalBookCasesCarpetArea=totalBookCasesCarpetArea+(bwidth*blength);
totalBookCasesPaintArea=totalBookCasesPaintArea+(bheight*blength);
}
//Commenting out hard coded values for number of doors,window and bookcases
/*out.print("\nEnter the Window1 height : ");
w1height = s.nextDouble();
out.print("\nEnter the Window1 width : ");
w1width = s.nextDouble();
out.print("\nEnter the Window2 height : ");
w2height = s.nextDouble();
out.print("\nEnter the Window2 width : ");
w2width = s.nextDouble();*/
/* out.print("\nEnter the bookshelf height : ");
bheight = s.nextDouble();
out.print("\nEnter the bookshelf width : ");
bwidth = s.nextDouble();
out.print("\nEnter the bookshelf length : ");
blength = s.nextDouble();*/
out.print("\nEnter the painting cost per square feet: $");
paintCost = s.nextDouble();
// out.print("\nEnter the carpenting cost per square feet: $");
// carpentCost = s.nextDouble();
out.print("\nChoose Flooring type : \n0: No Preferences\n1: Ceramic Tile \n2: Hardwood \n3: Carpet \n4: linoleum tile \n Enter Flooring type : ");
preferences = s.nextInt();
out.print("\nEnter your budget for flooring: ");
budget = s.nextDouble();
paintArea = 2 * rheight * (rwidth + rlength) - (totalBookCasesPaintArea) - (totalWindowSize) - (totalDoorSize); //calculation of paint area
carpentArea = (rwidth * rlength) - (totalBookCasesCarpetArea); //calculation of carpent area
/*paintArea = 2 * rheight * (rwidth + rlength) - (bheight * blength) - (w1width * w1height) - (w2width * w2height) - (dheight * dwidth); //calculation of paint area
carpentArea = (rwidth * rlength) - (bwidth * blength); //calculation of carpent area
*/ switch (preferences) {
case 0:
if (4 * carpentArea <= budget) {
carpentCost = 4;
flooring = "Ceramic Tile";
} else if (3 * carpentArea <= budget) {
carpentCost = 3;
flooring = "Hardwood";
} else if (2 * carpentArea <= budget) {
carpentCost = 2;
flooring = "Carpet";
} else if (1 * carpentArea <= budget) {
carpentCost = 1;
flooring = "Lenolieum Tile";
} else {
carpentCost = 0;
flooring = "";
}
break;
case 1:
if (4 * carpentArea <= budget) {
carpentCost = 4;
flooring = "Ceramic Tile";
} else {
carpentCost = 0;
}
break;
case 2:
if (3 * carpentArea <= budget) {
carpentCost = 3;
flooring = "Hardwood";
} else {
carpentCost = 0;
}
break;
case 3:
if (2 * carpentArea <= budget) {
carpentCost = 2;
flooring = "Carpet";
} else {
carpentCost = 0;
}
break;
case 4:
if (1 * carpentArea <= budget) {
carpentCost = 1;
flooring = "Lenolieum Tile";
} else {
carpentCost = 0;
}
break;
}
out.println("Area of wall after removing the paining area : " + paintArea);
out.println("Area of floor after removing area of bookshelf : " + carpentArea);
out.println("Cost for painting : $" + (paintArea * paintCost));
if (carpentCost != 0) {
out.println("flooring type : " + flooring);
out.println("Cost for flooring : $" + (carpentArea * carpentCost));
} else {
out.println("No Affordable flooring available in given budget");
}
}
}
/*
Renovation1
Enter the Room height : 12

Enter the Room width : 12

Enter the Room length : 12
Enter the Number of Doors: 3

Enter the Door1 height : 10

Enter the Door1 width : 2

Enter the Door2 height : 5

Enter the Door2 width : 3

Enter the Door3 height : 5

Enter the Door3 width : 3
Enter the Number of Windows: 0
Enter the Number of Bookcases: 1

Enter the bookshelf1 height : 10

Enter the bookshelf1 width : 2

Enter the bookshelf1 length : 8

Enter the painting cost per square feet: $1

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 0

Enter your budget for flooring: 255.00
Area of wall after removing the paining area : 446.0
Area of floor after removing area of bookshelf : 128.0
Cost for painting : $446.0
flooring type : Lenolieum Tile
Cost for flooring : $128.0

Renovation 2
Enter the Room height : 8

Enter the Room width : 12

Enter the Room length : 24
Enter the Number of Doors:
0
Enter the Number of Windows: 3

Enter the Window1 height : 6

Enter the Window1 width : 2

Enter the Window2 height : 5

Enter the Window2 width : 3

Enter the Window3 height : 5

Enter the Window3 width : 8
Enter the Number of Bookcases: 2

Enter the bookshelf1 height : 6

Enter the bookshelf1 width : 3

Enter the bookshelf1 length : 8

Enter the bookshelf2 height : 6

Enter the bookshelf2 width : 2

Enter the bookshelf2 length : 3

Enter the painting cost per square feet: $1.57

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 1

Enter your budget for flooring: 250.00
Area of wall after removing the paining area : 443.0
Area of floor after removing area of bookshelf : 258.0
Cost for painting : $695.51
No Affordable flooring available in given budget

Renovation 3
Enter the Room height : 12

Enter the Room width : 11.25

Enter the Room length : 12.75
Enter the Number of Doors: 1

Enter the Door1 height : 10

Enter the Door1 width : 1.95
Enter the Number of Windows: 2

Enter the Window1 height : 5

Enter the Window1 width : 2.5

Enter the Window2 height : 7.2

Enter the Window2 width : 6.8
Enter the Number of Bookcases: 1

Enter the bookshelf1 height : 6

Enter the bookshelf1 width : 3

Enter the bookshelf1 length : 8

Enter the painting cost per square feet: $0.95

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 3

Enter your budget for flooring: 400.00
Area of wall after removing the paining area : 447.04
Area of floor after removing area of bookshelf : 119.4375
Cost for painting : $424.688
flooring type : Carpet
Cost for flooring : $238.875

*/

Please write the code with comments for everything thank you! and don't use objects

(Java) Building a Doubly Linked List off of an interface I am having trouble with these two methods

    @Override
    public void add(T newEntry) {
        DoubleLinkedNode newNode = new DoubleLinkedNode(newEntry);

        if (!isEmpty()) {

        }
        if (isEmpty()) {
            first = newNode;
            last = newNode;
        } else {
            last.setNextNode(newNode);
            newNode.setPreviousNode(last);
            last = newNode;
        }
//        length++;
        numElements++;

    }

    @Override
    public void add(int newPosition, T newEntry) {
        DoubleLinkedNode newAdder = new DoubleLinkedNode(newEntry);

        if ((newPosition >= 0) && (newPosition <= numElements)) {
            numElements++;
            if (newPosition == 0) {
                add(newEntry);
            } else if (newPosition >= getLength() + 1) {
                DoubleLinkedNode previousNode = getNodeAt(newPosition - 1);
                DoubleLinkedNode NextNode = previousNode.getNextNode();

                newAdder.setNextNode(NextNode);
                newAdder.setPreviousNode(previousNode);
                previousNode.setNextNode(newAdder);
                NextNode.setPreviousNode(newAdder);
            } else if (newPosition == getLength()) {

                DoubleLinkedNode previousNode = getNodeAt(newPosition - 1);

                previousNode.setNextNode(newAdder);
                newAdder.setPreviousNode(previousNode);

                last = newAdder;
            }
        } else {
            throw new IndexOutOfBoundsException("");
        }
    }
I cannot figure out how to get the add newEntry and other add method to work All the Method calls do what you'd think they'd do

Q. An Operating system is an intermediary agent between the user and the computer hardware. Explain !

What volume, in milliliters, of 0.160 M0.160 M NaOH NaOH should be added to a 0.140 L0.140 L solution of 0.021 M0.021 M glycine hydrochloride (pKa1=2.350,Ka1=2.350, pKa2Ka2 = 9.7789.778) to adjust the pH to 2.61?

(java)

Create a specification(your choice) of a data abstraction , decide a rep for the data abstraction. Write the abstraction function and the rep invariant for the rep.

Note* add comments for explanation..

A data structure can be defined as a mechanism for organizing the data a program stores in memory. An example of a data structure is a Linked List. Discuss how a linked list works and the methods of this data structure. (Please be super detailed and type the solution)