You bought a house for $150,000 and put down 10% and got a mortgage at an interest rate of 4.35 % per year. You would pay it back by paying an equal amount at the end of each month for 15 years? (Show all work) How much is your loan amount? How much is your monthly loan payment? How much is your loan balance after 2 years? How much is your total interest payment by the end of year 3?

Medical Research Corporation is expanding its research and production capacity to introduce a new line of products. Current plans call for the expenditure of $100 million on four projects of equal size ($25 million each), but different returns. Project A is in blood clotting proteins and has an expected return of 18 percent. Project B relates to a hepatitis vaccine and carries a potential return of 14 percent. Project C, dealing with a cardiovascular compound, is expected to earn 11.8 percent, and Project D, an investment in orthopedic implants, is expected to show a 10.9 percent return.

The firm has $23,000,000 in retained earnings. After a capital structure with $23,000,000 million in retained earnings is reached (in which retained earnings represent 60 percent of the financing), all additional equity financing must come in the form of new common stock.

Common stock is selling for $26 per share and underwriting costs are estimated at $2.9 if new shares are issued. Dividends for the next year will be $0.71 per share (D₁), and earnings and dividends have grown consistently at 11% percent per year.

The yield on comparative bonds has been hovering at 10 percent. The investment banker feels that the first $19,500,000 of bonds could be sold to yield 10 percent while additional debt might require a 2 percent premium and be sold to yield 12 percent. The corporate tax rate is 30 percent. Debt represents 40 percent of the capital structure.

Design a 1-bt eror correction code for m=8 data bits and r=4 check bits. The 8 data bits are 10101011. For odd parity,assign the 4 check bits ,and give the 22 bits CODE WORD.

The price to earnings ratio (P/E) is an important tool in financial work. A random sample of 14 large U.S. banks (J. P. Morgan, Bank of America, etc) gave the following P/E ratios.

24, 16, 22, 14, 12, 13, 17, 22, 15, 19, 23, 13, 11, 18

Generally speaking, a low P/E ratio indicates a "value" or bargain stock. Financial publications indicated that the P/E ratio of the S&P 500 stock index has typically been 20.0. Let x be a random variable representing the P/E ratio of all large U.S. bank stocks. We assume that x has a normal distribution and σ = 4.1. Do these data indicate that the P/E ratio of all U.S. bank stocks is less than 20.0? Use α = 0.05.

(a) Enter the following. x =

s = (

b) Identify the claim, the null hypothesis, and the alternative hypothesis.

Claim: 20.0

Ho: 20.0

H1: 20.0

(c) Will you use a left-tailed, right-tailed, or two-tailed test? two-tailed left-tailed right-tailed

d) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.

The Student's t, since we assume that x has a normal distribution with known σ.

The standard normal, since n is large with known σ.

The standard normal, since we assume that x has a normal distribution with known σ.

The standard normal, since we assume that x has a normal distribution with unknown σ.

The standard normal, since n is large with unknown σ. The Student's t, since n is large with unknown σ.

(e) Sketch the sampling distribution showing the area corresponding to the approximate P-value.

(f) Will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?

At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.

At the α = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.

    At the α = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant

.At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant.

(g) State your conclusion in the context of the application.

Fail to reject the null hypothesis, there is insufficient evidence that average P/E for large banks is less than the S&P 500 Index.

Fail to reject the null hypothesis, there is sufficient evidence that average P/E for large banks is less than the S&P 500 Index.    

  Reject the null hypothesis, there is insufficient evidence that average P/E for large banks is less than the S&P 500 Index

.Reject the null hypothesis, there is sufficient evidence that average P/E for large banks is less than the S&P 500 Index.

As culturally aware mental health counselors what components of Social Class, within the United States, that includes Socioeconomic status, income, education, and children transitioning to adulthood from within these classes, upward and downward social mobility. Must we be mindful of in order to provide the best possible therapeutic outcome? What social injustice do various social classes face and what can be done to help advocate for change to provide social justice?

Q7.1    The normalized passband edge angular frequency Wp is - 0.2
   The normalized stopband edge angular frequency Ws is - 0.4
   The desired passband ripple Rp is - 0.5 dB
   The desired stopband ripple Rs is - 40 dB

In Matlab:

Q7.X1 Design a Butterworth lowpass filter satisfying the specifications in Q7.1. Plot the magnitude and phase responses. Also include magnified plots of passband and stopband showing how well the filter satisfies the design specifications.

Sometimes one of the hard things to determine is what type of research design to use when conducting research. Think about the following:

What are the strengths and weaknesses of using the correlational design? When are you most likely to use this design?

What are the strengths and weaknesses of using the descriptive design? When are you most likely to use this design?

What are the strengths and weaknesses of using an experimental design? When are you most likely to use this design?

1. Sustainability includes logistics design and can positively impact a business’s success.

True

False

2. Typically, Takt time is used in helping administer “Chase” scheduling techniques.

True

False

3. The name six sigma comes from the philosophy that a process should produce three standard deviations worth of output between the upper specification limit and the mean, plus three additional standard deviations worth of output between the lower specification limit and the mean, totaling six standard deviations worth of output between the upper and lower specification limits.

True

False

The language is java

package hw;

public class MyLinkedList<E> {
        SLLNode<E> head = null;
        public MyLinkedList() {} // O(1)
        public MyLinkedList(E[] elements) { // O(elements.length)
                for(int i=elements.length-1;i>=0;i--)
                        add(elements[i]);
        }
        public void printLinkedList() { // T(N) = O(N)
                System.out.print("printLinkedList(): ");
                SLLNode<E> node = head;
                while(node != null) {
                        System.out.print(node.info + " ");
                        node = node.next; // move to the next node
                }       
                System.out.println();
        }
        public void add(E e) { // T(N) = O(1)
                SLLNode<E> newNode = new SLLNode<E>(e);
                newNode.next = head;
                head = newNode;
        }
        public SLLNode<E> search(E e){// best-case: O(1)  worst-case: O(N)
                SLLNode<E> node = head;
                while(node != null) {
                        if(node.info.equals(e)) // check if node.info is equal to 'e'
                                return node;
                        node = node.next;
                }
                return null;    
        }
        public int remove(E e) { // best-case: O(1), worst-case: O(N)
                // if e is found, remove the node and return 1
                // if e is not found, return 0
                SLLNode<E> node = head;
                SLLNode<E> prev = null;
                while(node != null) {
                        if(node.info.equals(e)) {
                                if(prev == null) 
                                        head = node.next;
                                else    
                                        prev.next = node.next;
                                return 1;
                        }
                        prev = node;
                        node = node.next;
                }
                return 0;
        }
        public int size() { // O(N)
                // return the number of elements in the linked list
                SLLNode<E> node = head;
                int count=0;
                while(node != null) {
                        count++;
                        node = node.next;
                }
                return count;                   
        }
        public void repeatEach() { // O(N)
                // duplicate each element in the list
                // eg) this list has [10, 20, 30] and this method change it to [10, 10, 20, 20, 30, 30];
                SLLNode<E> node = head;
                SLLNode<E> newNode;
                
                while(node != null) {
                        newNode = new SLLNode<E>(node.info);
                        newNode.next = node.next;
                        node.next = newNode;
                        node = newNode.next; //node.next.next;
                }
        }
        public void clear() { // O(1)
                head = null;
        }
        public boolean isEmpty() { return head == null;}; // O(1)
        public boolean isFull() { return false; }       // O(1)
        
        public E get(int idx) { // O(idx)
                // return the value at the given index
                // eg) For a list {10,20,30,40}, get(2) will return 30
                // Assume that idx is valid, i.e. 0<= idx < size()
        }
        public void set(int idx, E val) { // O(idx)
                // set the node's value at the given index with given value
                // eg) For a list {10,20,30,40}, set(2,100) will change it into {10,20,100,40}
                // Assume that idx is valid, i.e. 0<= idx < size()
        }
        public void addAt(int idx, E val) { // O(idx)
                // insert a node of given value at the given index while pushing some nodes to the right
                // eg) For a list {10,20,30,40}, addAt(2,100) will change it into {10,20,100,30,40}
                // Hint: You may want to stop at idx-1 position to make connections.
                // Assume that idx is valid, i.e. 0<= idx <= size()
        }
        public E[] toArray() { // O(numElements)
                // return an array that contains all the elements(numbers) in the list
        }
        public MyLinkedList<E> clone() { // O(numElements)
                // return a copy of 'this' object. 
                // Any change made to the copy should be independent of this object.
        }
        public void removeAll(E val) { // O(numElements)
                // remove all the nodes with given value
                // This is a bonus problem (+5 points). 
                // It is hard. Don't spend too much time on this. You don't lose points if you don't do this.
        }
}

**DIFFERENT FILE**

package hw;

public class MyLinkedListDemo {
        static void printArray(Object[] objs){          
                for(int i=0; i<objs.length;i++)              
                        System.out.print(objs[i]+" ");  
                System.out.println();                                   
        }
        public static void main(String[] args) {
                
                MyLinkedList<Integer> mynums1 = new MyLinkedList<Integer>(new Integer[] {1, 2, 3, 4, 5});
                mynums1.printLinkedList();
                
//              // testing get()
//              System.out.println(mynums1.get(0));
//              System.out.println(mynums1.get(1));
//              System.out.println(mynums1.get(4));
//              
//              // testing set(idx,val)
//              mynums1.set(1,10); mynums1.printLinkedList();
//              mynums1.set(4,20); mynums1.printLinkedList();
//              mynums1.set(0,50); mynums1.printLinkedList();

//              // testing addAt(idx,val)
//              mynums1.addAt(5,300); mynums1.printLinkedList();
//              mynums1.addAt(5,100); mynums1.printLinkedList();
//              mynums1.addAt(0,200); mynums1.printLinkedList();

//              // testing toArray()
//              printArray(mynums1.toArray());
                
//              // testing removeAll()
//              MyLinkedList<Integer> mynums2 = new MyLinkedList<Integer>(new Integer[] {1, 1, 2, 2, 2, 3, 1, 2, 3, 2, 2});
//              mynums2.printLinkedList();
//              mynums2.removeAll(2); mynums2.printLinkedList();
//              mynums2.removeAll(1); mynums2.printLinkedList();
//              mynums2.removeAll(3); mynums2.printLinkedList();
        }
}

: Financial Statement Analysis

The following are BAC Bhd.’s year end statement of financial position and statement of profit and loss for 2016 and 2017:
2017 ($) 2016 ($)
Non Current Assets:   
Gross Non Current assets 317,503 232,179
Less accumulated depreciation 54,045 34,187
Net Non Current assets 263,458 197,992
Current Assets:
ICLBAT/JANUARY2019
7

Cash and equivalents 208,323 102,024
Accounts receivable 690,294 824,979
Inventories 942,374 715,414
Total Current Aassets 1,840,991 1,642,417
Total Assets 2,104,449 1,840,409
Non Current Liabilities   
Long term debt 410,769 372,931
Total Non Current Liabilities 410,769 372,931
Current Liabilites   
Short term borrowings 288,798 296,149
Accounts payable 636,318 414,611
Accruals 106,748 103,362
Total Current Liabilities 1,031,864 814,122
Total Liabilities 1,442,633 1,187,053
Shareholders’ Equity   
Common stock (100,000 shares) 550,000 550,000

Retained earnings 111,816 103,356
Total Shareholders’ Equity 661,816 653,356
Total Liabilities and Shareholders’ Equity 2,104,449 1,840,409

2017 ($) 2016 ($)
Sales 2,325,967 2,220,607 (-) Cost of goods sold 1,869,326 1,655,827 Other expenses 287,663 273,870 Total operating costs excluding depreciation and amortization 2,156,989 1,929,697 Depreciation and amortization 25,363 26,341 Total operating costs 2,182,352 1,956,038 EBIT 143,615 264,569 (-) Interest expense 31,422 13,802 EBT 112,193 250,767 (-) Taxes (30%) 33,658 75,230 Net income 78,535 175,537

Related items:
2017 2016 Total dividends paid $70,075 $150,000 Stock price per share $15.60 $21.80

Required:
(a) Calculate the after tax operating income (i.e. after-tax EBIT) for 2016 and 2017.

(b) Calculate the net working capital (NWC) that is supported by non-free sources for 2016 and 2017, and the changes in NWC between these two years.

(c) What is free cash flow (FCF)? Calculate the FCF for 2017. Is a negative FCF always a bad sign?

(d) Calculate the following for the company for 2017: (i) Earnings per share (1 mark) (ii) Dividends per share (1 mark) (iii) Book value per share (1 mark) (Total: 15 marks)

Calculate the pH of the solution resulting from the addition of 10.0 mL of 0.10 M NaOH to 50.0 mL of a 0.10 M solution of aspirin (acetylsalicic acid, K_a = 3.0 × 10^–4) solution.

6.(a) Show that if f : [a,b]→R is Riemann integrable and if m ≤ f (t) ≤ M holds
for all t in the subinterval [c,d] of [a,b], then
m(d −c) ≤ ∫_c^d f(t) dt ≤ M(d −c). (that is supposed to be f integrated from c to d)

(b) Prove the fundamental theorem of calculus, in the form given in the Introduction
to this book. (Hint: Use part (a) to estimate F(x)−F(x₀)/x−x₀.)

A Diesel cycle engine is analyzed using the air standard method. Given the conditions at state 1, compression ratio (r), and cutoff ratio (rc) determine the efficiency and other values listed below.

Note: The gas constant for air is R=0.287 kJ/kg-K.

Given Values

T1 (K) = 338

P1 (kPa) = 130

r = 14.5

rc = 1.25

a) Determine the specific internal energy (kJ/kg) at state 1.

b) Determine the relative specific volume at state 1.

c) Determine the relative specific volume at state 2.

d) Determine the temperature (K) at state 2.

e) Determine the pressure (kPa) at state 2.

f) Determine the specific enthalpy (kJ/kg) at state 2.

g) Determine the temperature (K) at state 3.

h) Determine the pressure (kPa) at state 3.

i) Determine the specific enthalpy (kJ/kg) at state 3.

j) Determine the relative specific volume at state 3.

k) Determine the relative specific volume at state 4.

l) Determine the temperature (K) at state 4.

m) Determine the pressure (kPa) at state 4.

n) Determine the specific internal energy (kJ/kg) at state 4.

o) Determine the net work per cycle (kJ/kg) of the engine.

p) Determine the heat addition per cycle (kJ/kg) of the engine.

q) Determine the efficiency (%) of the engine.

IE212-LEAN PROCESS

Suppose that we have a process that produces two types of an item: Blue Item and Orange Item. Both of the items require the same pure sequential operations: O1, O2, O3. O1 and O3 are manual operations. O2 is the main and an automated operation which differentiates the items (e.g. gives different colors). Operation 1 takes 1 minutes per item. It is a manual operation that is common to both types. Operation 2 takes 4 minutes per item. It is an automated operation. Operation 3 takes 2 minute per item. It is a manual operation that is common to both types. Draw the GANTT Chart, calculate the flow time, cycle time, throughput, value added time and waste when the setup time for machine 2 where the Operation 2 occurs is 2 minutes and the batch size is 3 items per batch.