In: Statistics and Probability
Sample grade point averages for ten male students and ten female students are listed. Find the coefficient of variation for each of the two data sets. Then compare the results. Males 2.6 3.8 3.9 3.8 2.7 2.6 3.4 3.5 3.8 1.8 Females 2.7 3.9 2.2 3.8 3.5 4.1 2.1 3.8 3.9 2.5 The coefficient of variation for males is nothing%. (Round to one decimal place as needed.)
No.of Sample |
10 |
Mean | 3.19 |
Standard Deviation | 0.7171 |
Coefficient of Variance | 0.2247 |
Step by Step Calculation: Input: 2.6, 3.8, 3.9, 3.8, 2.7, 2.6, 3.4, 3.5, 3.8, 1.8 |
Standard deviation = sqrt [ sum ( Xi - mean )2 / n - 1] =0.7171
= Sqrt( (1/10-1) *
(2.6-3.19)2+(3.8-3.19)2+(3.9-3.19)2+(3.8-3.19)2+(2.7-3.19)2+(2.6-3.19)2+(3.4-3.19)2+(3.5-3.19)2+(3.8-3.19)2+(1.8-3.19)2)
= Sqrt( (1/9) * (-0.592 + 0.612 + 0.712 + 0.612 + -0.492 + -0.592 +
0.212 + 0.312+ 0.612 + -1.392))
= Sqrt( (1/9) * (0.3481 + 0.3721 + 0.5041 + 0.3721 + 0.2401 +
0.3481 + 0.0441 + 0.0961 + 0.3721 + 1.9321))
= Sqrt(0.51423241)
S= 0.7171
Coefficient of Variance = s/µ
= 0.7171 / 3.19
Coefficient of Variance = 0.2247
Male coefficient of variation = 0.2247 ~ 22.5 %
No.of Samples | 10 |
Mean | 3.25 |
Standard Deviation | 0.7835 |
Coefficient of Variance | 0.241 |
Step by Step Calculation: Input: 2.7, 3.9, 2.2, 3.8, 3.5, 4.1, 2.1, 3.8, 3.9, 2.5 |
Standard deviation =
= Sqrt( (1/10-1) *
(2.7-3.25)2+(3.9-3.25)2+(2.2-3.25)2+(3.8-3.25)2+(3.5-3.25)2+(4.1-3.25)2+(2.1-3.25)2+(3.8-3.25)2+(3.9-3.25)2+(2.5-3.25)2)
= Sqrt( (1/9) * (-0.552 + 0.652 + -1.052 + 0.552 + 0.252 + 0.852 +
-1.152 + 0.552 + 0.652 + -0.752))
= Sqrt( (1/9) * (0.3025 + 0.4225 + 1.1025 + 0.3025 + 0.0625 +
0.7225 + 1.3225 + 0.3025 + 0.4225 + 0.5625))
= Sqrt( 0.61387225)
S= 0.7835
Coefficient of Variance = s/µ
= 0.7835 / 3.25
Coefficient of Variance = 0.241
Female coefficient of variation = 0.241 ~ 24.1 %
Female C.V. is greater than male C.V